Given that,
Last year record = 12
This year record = 15.
To find,
The percent increase of his Collection.
Solution,
The percent increase in his collection is given by :

So, the percent increase of his collection is 25%.
Answer:
1, 2, 6
Step-by-step explanation:
The z score shows by how many standard deviations the raw score is above or below the mean. The z score is given by:

Given that mean (μ) = 130 texts, standard deviation (σ) = 20 texts
1) For x < 90:

From the normal distribution table, P(x < 90) = P(z < -2) = 0.0228 = 2.28%
Option 1 is correct
2) For x > 130:

From the normal distribution table, P(x > 130) = P(z > 0) = 1 - P(z < 0) = 1 - 0.5 = 50%
Option 2 is correct
3) For x > 190:

From the normal distribution table, P(x > 3) = P(z > 3) = 1 - P(z < 3) = 1 - 0.9987 = 0.0013 = 0.13%
Option 3 is incorrect
4) For x < 130:

For x > 100:

From the normal table, P(100 < x < 130) = P(-1.5 < z < 0) = P(z < 0) - P(z < 1.5) = 0.5 - 0.0668 = 0.9332 = 93.32%
Option 4 is incorrect
5) For x = 130:

Option 5 is incorrect
6) For x = 130:

Since 1.5 is between 1 and 2, option 6 is correct
Answer:
54
Step-by-step explanation:
4 ÷ 2 + 52
Order of operation
= 2 + 52
= 54
He walked 2,525 m per an hour.
11,040 - 920 = 10,100
10,100 / 4 = 2,525
Please mark brainliest.
Answer:
8 and 5
Step-by-step explanation: