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Diano4ka-milaya [45]
3 years ago
5

PLease help geometry question

Mathematics
2 answers:
nata0808 [166]3 years ago
8 0

Let the length equal x

Then the width would be 4x + 8 (8 feet more than 4 times the length)

Area = length x width:

5,472 = x * 4x+ 8

Simplify:

5472 = 4x^2 + 8x

Subtract 5472 from both sides:

4 x^2 + 8x - 5472 = 0

Use the quadratic formula to solve for x.

X = 36

Now you know the length is 36 feet

The width = 4(36) + 8 = 152 feet

Now find the perimeter: 152 + 152 + 36 + 36 = 376 feet.

The answer is B. 376

Natalija [7]3 years ago
6 0

Let the length equal x

Then the width would be 4x + 8 (8 feet more than 4 times the length)

Area = length x width:

5,472 = x * 4x+ 8

Simplify:

5472 = 4x^2 + 8x

Subtract 5472 from both sides:

4 x^2 + 8x - 5472 = 0

Use the quadratic formula to solve for x.

X = 36

Now you know the length is 36 feet

The width = 4(36) + 8 = 152 feet

Now find the perimeter: 152 + 152 + 36 + 36 = 376 feet.

The answer is B. 376

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professor190 [17]

Answer:

The variance and standard deviation of <em>X</em> are 0.48 and 0.693 respectively.

The variance and standard deviation of (20 - <em>X</em>) are 0.48 and 0.693 respectively.

Step-by-step explanation:

The variable <em>X</em> is defined as, <em>X</em> = number of defective items in the sample.

In a sample of 20 items there are 4 defective items.

The probability of selecting a defective item is:

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A random sample of <em>n</em> = 3 items are selected at random.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 3 and <em>p </em>= 0.20.

The variance of a Binomial distribution is:

V(X)=np(1-p)

Compute the variance of <em>X</em> as follows:

V(X)=np(1-p)=3\times0.20\times(1-0.20)=0.48

Compute the standard deviation (σ (X)) as follows:

\sigma (X)=\sqrt{V(X)}=\sqrt{0.48}=0.693

Thus, the variance and standard deviation of <em>X</em> are 0.48 and 0.693 respectively.

Now compute the variance of (20 - X) as follows:

V(20-X)=V(20)+V(X)-2Cov(20,X)=0+0.48-0=0.48

Compute the standard deviation of (20 - X) as follows:

\sigma (20-X)=\sqrt{V(20-X)} =\sqrt{0.48}0.693

Thus, the variance and standard deviation of (20 - <em>X</em>) are 0.48 and 0.693 respectively.

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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[-16,-4]

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