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3 years ago

PLease help geometry question

Mathematics

2 answers:

nata0808 [166]3 years ago

8 0

Let the length equal x

Then the width would be 4x + 8 (8 feet more than 4 times the length)

Area = length x width:

5,472 = x * 4x+ 8

Simplify:

5472 = 4x^2 + 8x

Subtract 5472 from both sides:

4 x^2 + 8x - 5472 = 0

Use the quadratic formula to solve for x.

X = 36

Now you know the length is 36 feet

The width = 4(36) + 8 = 152 feet

Now find the perimeter: 152 + 152 + 36 + 36 = 376 feet.

The answer is B. 376

Natalija [7]3 years ago

6 0

Let the length equal x

Then the width would be 4x + 8 (8 feet more than 4 times the length)

Area = length x width:

5,472 = x * 4x+ 8

Simplify:

5472 = 4x^2 + 8x

Subtract 5472 from both sides:

4 x^2 + 8x - 5472 = 0

Use the quadratic formula to solve for x.

X = 36

Now you know the length is 36 feet

The width = 4(36) + 8 = 152 feet

Now find the perimeter: 152 + 152 + 36 + 36 = 376 feet.

The answer is B. 376

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ExtremeBDS [4]

Answer:

To find the surface area of a cube, use the formula: surface area = 6s^2, where s is the length of one of the sides. If you don't know the length of the sides, you can find the surface area using volume. Just find the cube root of the volume, which is equal to the length of one side of the cube.

Step-by-step explanation:

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2 years ago

A square has a perimeter of 40 m. What is the length of each side?

bekas [8.4K]

Answer:

10 m

Step-by-step explanation:

A square has all equal side lengths. If that is the case, the we have 4 sides that equal each other:

x + x + x + x = 40 m

4x = 40m

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7 0

3 years ago

Read 2 more answers

Two boats leave the same place at the same time. The first boat heads due north at 10 kilometers per hour. The second boat heads

Maksim231197 [3]

Answer:

18.87 km/hr

Step-by-step explanation:

First boat is heading North with a speed of 10 km/hr.

Second boat is heading West with a speed of 16 km/hr.

Time for which they move = 2.5 hours

To find:

The speed at which the distance is increasing between the two boats.

Solution:

Let the situation be represented by the attached diagram.

Their initial position is represented by point O from where they move towards point A and point B respectively.

$Distance = Speed \times Time$

$Distance\ OA = 10 \times 2.5 = 25\ km$

$Distance\ OB = 16 \times 2.5 = 40\ km$

We can use Pythagorean Theorem to find the distance AB.

AB is the hypotenuse of the right angled $\triangle AOB$ .

According to Pythagorean theorem:

$\text{Hypotenuse}^{2} = \text{Base}^{2} + \text{Perpendicular}^{2}\\\Rightarrow AB^{2} = OA^{2} + OB^{2}\\\Rightarrow AB^2 = 25^2 + 40^2\\\Rightarrow AB^2 = 2225^2\\\Rightarrow AB^2 \approx 47.17\ km$