Answer:
<h2>3.6°</h2>
Step-by-step explanation:
The question is incomplete. Here is the complete question.
Find the angle between the given vectors to the nearest tenth of a degree.
u = <8, 7>, v = <9, 7>
we will be using the formula below to calculate the angle between the two vectors;

is the angle between the two vectors.
u = 8i + 7j and v = 9i+7j
u*v = (8i + 7j )*(9i + 7j )
u*v = 8(9) + 7(7)
u*v = 72+49
u*v = 121
|u| = √8²+7²
|u| = √64+49
|u| = √113
|v| = √9²+7²
|v| = √81+49
|v| = √130
Substituting the values into the formula;
121= √113*√130 cos θ
cos θ = 121/121.20
cos θ = 0.998
θ = cos⁻¹0.998
θ = 3.6° (to nearest tenth)
Hence, the angle between the given vectors is 3.6°
100-15=85
Therefore 0.85 is the multiplier
So 243.00 times by 0.85 = 206.55
Answer:
12 * 10 ^ 7
Step-by-step explanation:
3 * 10 ^ 2 * 4 * 10 ^5
= 12 * 10^ 2 + 5
= 12 * 10 ^ 7
Hope it will help :)
Answer:

Step-by-step explanation:
Answer:
-6
Step-by-step explanation:
-2x - 3 = 9
+ 3 +3
-2x = 12
/ -2 / -2
x = -6