First option: About the same
Second option: Greater for conference A than B
Hope it helps!
The sum of the two <em>rational</em> equations is equal to (3 · n² + 5 · n - 10) / (3 · n³ - 6 · n²).
<h3>How to simplify the addition between two rational equations</h3>
In this question we must use <em>algebra</em> definitions and theorems to simplify the addition of two <em>rational</em> equations into a <em>single rational</em> equation. Now we proceed to show the procedure of solution in detail:
- (n + 5) / (n² + 3 · n - 10) + 5 / (3 · n²) Given
- (n + 5) / [(n + 5) · (n - 2)] + 5 / (3 · n²) x² - (r₁ + r₂) · x + r₁ · r₂ = (x - r₁) · (x - r₂)
- 1 / (n - 2) + 5 / (3 · n²) Associative and modulative property / Existence of the multiplicative inverse
- [3 · n² + 5 · (n - 2)] / [3 · n² · (n - 2)] Addition of fractions with different denominator
- (3 · n² + 5 · n - 10) / (3 · n³ - 6 · n²) Distributive property / Power properties / Result
To learn more on rational equations: brainly.com/question/20850120
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Answer:
2+2=4 thank you and can I get brainlest too
Answer:
The required answer is 
.
Step-by-step explanation:
Consider the provided numbers:
We need to subtract in base 4.
The place value of 201 is:
1 is at units place, 0 is at four's place and 2 is at 4 squared place.
The place value of 32 is:
2 is at units place and 3 is at four's place.
201
- 32
Start subtracting the numbers from the unit place.
Here, we need to subtract 2 from 1, which is not possible so borrow 4 from the four's place but there is 0 at four's place so borrow from 4 squared place and change 2 to 1.
Also change 0 to 4 because we have borrow 4 from squared place.
Now 1 can borrow 4 from the four's place which will become 1+4=5 and change 4 at four's place to 3.
Now the number will look like this:
135
- 32
Now subtract the number as shown.
135
<u>- 32</u>
103
Hence, the required answer is .
