All categories

1 year ago

Which is true about the domain and range of a function in the form f(x) = m√x, where m is a real number greater

Mathematics

1 answer:

sveticcg [70]1 year ago

6 0

There is an infinite number of values that are in both the domain and range.

<h3>Define domain and range.</h3>

The range of values that we are permitted to enter into our function is known as the domain of a function. The x values for a function like f make up this set (x). A function's range is the collection of values it can take as input. After we enter an x value, the function outputs this sequence of values. The collection of all potential inputs for a function is its domain.

Given Data

Range of a function in the form f(x) = m√x, where m is a real number greater than 0

There is an infinite number of values that are in both the domain and range.

The range of a function always has an unlimited number of values when the domain of the function does. The claim is untrue because more than one input and output might have been matched.

To learn more about domain and range, visit:

brainly.com/question/28135761

#SPJ13

You might be interested in

John rides his bike with a constant speed of 20 km/h. How far can he travel in 2 1/2 hours?

Olegator [25]

Ok so,

20*2= 40

20*1/2=10

40+10=50

So Johncan travel 50 km in 2 1/2 hours.

Hope this helps :)

4 0

3 years ago

A number is divisible by 3 if the sum of the digits of the number is divisible by 3.

rosijanka [135]

I believe the answer the the question A number is divisible by 3 if the sum of the digits of the number is divisible by 3. Is 504, it makes sense

8 0

3 years ago

Write and equation for the line that has a slope of one half and passes through the point 2,4

jekas [21]

The equation in slope intercept form is

Y=.5x+3

8 0

3 years ago

I need some help with this

Mashutka [201]

The angle of elevation from the hiker to the park ranger is the same as the angle of depression from the ranger to the hiker, 29°.

The tangent function of an angle is the ratio of the opposite side (500') to the adjacent side (x) in the right triangle shown. That is
tan(29°) = 500' / x

Multiplying the equation by x/tan(29°) gives
x = 500' / tan(29°)
x ≈ 500' / 0.5543
x ≈ 902 ft

6 0

3 years ago

If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by

Vitek1552 [10]

Answer:

a) Average velocity at 0.1 s is 696 ft/s.

b) Average velocity at 0.01 s is 7536 ft/s.

c) Average velocity at 0.001 s is 75936 ft/s.

Step-by-step explanation:

Given : If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by $y = 70t-16t^2$ .

To find : The average velocity for the time period beginning when t = 2 and lasting. a. 0.1 s. , b. 0.01 s. , c. 0.001 s.

Solution :

a) The average velocity for the time period beginning when t = 2 and lasting 0.1 s.

$(\text{Average velocity})_{0.1\ s}=\frac{\text{Change in height}}{0.1}$

$(\text{Average velocity})_{0.1\ s}=\frac{h_{2.1}-h_2}{0.1}$

$(\text{Average velocity})_{0.1\ s}=\frac{(70(2.1)-16(2.1)^2)-(70(0.1)-16(0.1)^2)}{0.1}$

$(\text{Average velocity})_{0.1\ s}=\frac{69.6}{0.1}$

$(\text{Average velocity})_{0.1\ s}=696\ ft/s$

b) The average velocity for the time period beginning when t = 2 and lasting 0.01 s.

$(\text{Average velocity})_{0.01\ s}=\frac{\text{Change in height}}{0.01}$

$(\text{Average velocity})_{0.01\ s}=\frac{h_{2.01}-h_2}{0.01}$

$(\text{Average velocity})_{0.01\ s}=\frac{(70(2.01)-16(2.01)^2)-(70(0.01)-16(0.01)^2)}{0.01}$

$(\text{Average velocity})_{0.01\ s}=\frac{75.36}{0.01}$

$(\text{Average velocity})_{0.01\ s}=7536\ ft/s$

c) The average velocity for the time period beginning when t = 2 and lasting 0.001 s.

$(\text{Average velocity})_{0.001\ s}=\frac{\text{Change in height}}{0.001}$

$(\text{Average velocity})_{0.001\ s}=\frac{h_{2.001}-h_2}{0.001}$

$(\text{Average velocity})_{0.001\ s}=\frac{(70(2.001)-16(2.001)^2)-(70(0.001)-16(0.001)^2)}{0.001}$

$(\text{Average velocity})_{0.001\ s}=\frac{75.936}{0.001}$

$(\text{Average velocity})_{0.001\ s}=75936\ ft/s$

5 0

4 years ago