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VARVARA [1.3K]
3 years ago
13

What is the solution to the equation 4x = 44? x = 4 x = 10 x = 11 x = 40

Mathematics
2 answers:
anyanavicka [17]3 years ago
5 0

Answer:

x = 11

Step-by-step explanation:

Divide both sides of the equation by 4.

... (4x)/4 = (44)/4

... x = 11 . . . . simplify

_____

You could probably work this in 3rd grade in the form 4 × ___ = 44. In Algebra, we give a name (x) to the blank. It is the same problem. Your knowledge of number relationships (multiplication tables) still applies.

Kitty [74]3 years ago
5 0
<h2>Answer:</h2><h2>It equals 11</h2><h2>Step-by-step explanation:</h2>

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What is the lowest common multiple of 24 and 40
geniusboy [140]

24 = 4*6 = 2*2 * 2 *3

40 = 4*10 = 2*2 *2 *5

least common multiple is 2*2*2*3*5

120

6 0
3 years ago
Please help me ......:(
algol [13]

Answer:  B) F(x) = √x and G(x) = 3x + 2

<u>Step-by-step explanation:</u>

The composite function G(F(x)) is when you replace every x-value in the G(x) function with the F(x) function.

A)\ G(3x+2) = \sqrt{3x+2}\\\\B)\ G(\sqrt{x})=3(\sqrt{x})+2\quad =3\sqrt{x}+2\\\\C)\ G(\sqrt{x}+2) = 3\quad \text{there are no x-values in the G(x) function to replace}\\\\D) G(3\sqrt{x})=2\quad \text{there are no x-values in the G(x) function to replace}

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5 0
3 years ago
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Alona [7]
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5 0
3 years ago
A machine operation produces bearings whose diameters are normally distributed, with a mean of 0.497 inch and a standard deviati
eduard
Mean = 0.497 in, SD = 0.003 in
Required diameter ranges between 0.496 in and 0.504 in
Anything other diameter obtained is not acceptable.

That is;
P(x<0.496) and P(x>0.504) are not acceptable.

Now,
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From Z tables, P(Z<-0.33) = 0.3707

Similarly,
P(x>0.504) = P(Z> (0.504-0.497)/0.003)) = P(Z>2.33)
From Z tables, P(Z>2.33) = 1-0.9901 = 0.0099

Therefore, unacceptable proportion = P(x<0.496)+P(x>0.504) = 0.3707+0.0099 = 0.3806 or 38.06%
6 0
3 years ago
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Alisiya [41]

Answer:

Complex roots [Refer picture]

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I am not sure if it's correct.

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8 0
3 years ago
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