Triangle RTS is congruent to RQS by AAS postulate of congruent
Step-by-step explanation:
Let us revise the cases of congruence
- SSS ⇒ 3 sides in the 1st Δ ≅ 3 sides in the 2nd Δ
- SAS ⇒ 2 sides and including angle in the 1st Δ ≅ 2 sides and including angle in the 2nd Δ
- ASA ⇒ 2 angles and the side whose joining them in the 1st Δ ≅ 2 angles and the side whose joining them in the 2nd Δ
- AAS ⇒ 2 angles and one side in the 1st Δ ≅ 2 angles
and one side in the 2nd Δ
- HL ⇒ hypotenuse leg of the 1st right Δ ≅ hypotenuse leg of the 2nd right Δ
∵ SR bisects angle TSQ ⇒ given
∴ ∠TSR ≅ ∠QSR
∴ m∠TSR ≅ m∠QSR
∵ ∠T ≅ ∠Q ⇒ given
∴ m∠T ≅ m∠Q
In two triangles RTS and RQS
∵ m∠T ≅ m∠Q
∵ m∠TSR ≅ m∠QSR
∵ RS is a common side in the two triangle
- By using the 4th case above
∴ Δ RTS ≅ ΔRQS ⇒ AAS postulate
Triangle RTS is congruent to RQS by AAS postulate of congruent
Learn more:
You can learn more about the congruent in brainly.com/question/3202836
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Answer:
The answer is - 113 that is the correct answer skipping in three's and the first one is - 97
A) f(x) is decreasing because the base is less than 1.
0.56 is close to 0.5, so its like saying that you are taking half each time, therefore the value is getting smaller.
g(x) is increasing because the base is greater than 1.
you are multiplying by 4 each time, making the value bigger.
B ) The y-intercept is where x=0.
Anything to the '0' power is 1. Therefore the y-intercept is equal to the coefficient in front of each function.
f(x) = 3 , g(x) = 6
C) Just plug in x=4 to each function in a calculator.
f(4) = 0.295
g(4) = 1536
No because think about 12 and 6. the greatest common factor is 3 which isn't even
Pythagorean theorem is formula we would use:
1.)
c^2=a^2+b^2
c^2=10^2+24^2
c^2=100+576
c^2=676
c= √676
c=26 in
2.)
c^2=7^2+14^2
c^2=49+196
c^2=245
c= √245
c~15.65 cm
