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3 years ago

Convert 1200 degrees into radians

Mathematics

2 answers:

Bond [772]3 years ago

7 0

The answer is 20.943951

poizon [28]3 years ago

4 0

The answer to ur question is 20.94395.

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Please help. will mark brainliest

Semmy [17]

DH = HF

x + 1 = 3y

y = (x + 1) ⁄ 3

GH = HE

3x – 4 = 5y + 1

y = (3x – 5) ⁄ 5

y = y

(x + 1) ⁄ 3 = (3x – 5) ⁄ 5

5x + 5 = 9x – 15

4x = 20

x = 5

y = (x + 1) ⁄ 3

y = (5 + 1) ⁄ 3

y = 2

4 0

3 years ago

Match each scenario with the tax it is describing by putting the correct number next t

Anna [14]

Answer:

1) Yvonne buys gloves that cost $10.00. At the register, she must pay $10.80. ⇒ EXCISE TAX

2)Sasha bought a house last year. She just got a tax bill from the county showing the value of her house and the amount of tax. ⇒ PROPERTY TAX

3) Bigmart sells boots made in China and boots made in the U.S. Bigmart must pay 27% tax on each pair of boots made in China, but not on the U.S. made boots. ⇒ TARRIFF.

4)State citizens voted to add a 75-cent tax to each pack of cigarettes to pay for programs to help people quit smoking. ⇒ SALES TAX

5)Jake got his paycheck today. He worked 40 hours at $20 per hour His gross pay was $800, but the amount of his paycheck was only. ⇒ Income/Social /Security/Medicare Taxes

8 0

3 years ago

Read 2 more answers

g Suppose a factory production line uses 3 machines, A, B, and C for making bolts. The total output from the line is distributed

Vladimir [108]

Answer:

The probability that it came from A, given that is defective is 0.362.

Step-by-step explanation:

Define the events:

A: The element comes from A.

B: The element comes from B.

C: The element comes from C.

D: The elemens is defective.

We are given that P(A) = 0.25, P(B) = 0.35, P(C) = 0.4. Recall that since the element comes from only one of the machines, if an element is defective, it comes either from A, B or C. Using the probability axioms, we can calculate that

$P(D) = P(A\cap D) + P(B\cap D) + P(C\cap D)$

Recall that given events E,F the conditional probability of E given F is defined as

$P(E|F) = \frac{P(E\cap F)}{P(F)}$ , from where we deduce that

$P(E\cap F) = P(E|F)P(F)$ .

We are given that given that the element is from A, the probability of being defective is 5%. That is P(D|A) =0.05. Using the previous analysis we get that

$P(D) = P(A)P(D|A)+P(B) P(D|B) + P(C)P(D|C) = 0.05\cdot 0.25+0.04\cdot 0.35+0.02\cdot 0.4 = 0.0345$