your class is making a rectangular poster for a rally. the posters design is 6 in. high by 10 in. wide. the space allowed for th

Question

3 years ago

11

e poster is 4 ft high by 8 ft wide. what are the dimensions of the largest poster that will fit in the space?

2 answers:

Nitella [24] · Answer 1 · 2022-05-06T15:59:53+03:00

7 0

Answer:I would assume it is, 4in. High, by 8in. Wide

Step-by-step explanation:

6-2=4

10-2=8

Space = 8x4 = 32in2

New poster = 4x8=32in2

(I hope this is correct)

Kay [80] · Answer 2 · 2022-05-06T13:30:33+03:00

I FOUND YOUR COMPLETE QUESTION IN OTHER SOURCES.

PLEASE SEE ATTACHED IMAGE.

For this case the area is given by:

A = (22 + x) * (28 + x) = 722

Rewriting we have:

616 + 22x + 28x + x ^ 2 = 722

x ^ 2 + 50x + 616 - 722 = 0

x ^ 2 + 50x - 106 = 0

Solving the polynomial we have:

x1 = 2.04

x2 = -52.04

We take the positive root:

x = 2.04 inches:

Answer:

The width of the border to the nearest inch is:

x = 2inches