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tekilochka [14]
3 years ago
12

8 litres of paint can cover 129.6 m². How much paint is required to paint an area of 243m²?

Mathematics
1 answer:
pshichka [43]3 years ago
7 0

Answer:

15 litres

Step-by-step explanation:

129.6 m² needs 8L

1m² needs 8/129.6L

243m² needs (8/129.6)×243 = 15L

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Please help! Thanks! The midpoint between y and 33 is -7. Find y
Setler79 [48]

Answer: 32

Step-by-step explanation: hope this helps

4 0
3 years ago
{y=x−75x+2y=7<br> Use the substitution method.<br><br> (0, −7)<br> (3, −4)<br> (7, 0)<br> (−1, −8)
harkovskaia [24]
<span>A) y=x−7
B) </span><span><span>5</span>x+2y=7
A) x = y + 7
Substituting this into B)
</span>
<span>y + 7 +2y = 7
</span>
3y = 0
y = 0
x = 7

Answer is C (7,0)

4 0
4 years ago
find the angle between the vectors. (first find the exact expression and then approximate to the nearest degree. ) a=[-8,6]. B=[
just olya [345]

Answer:

49°

Step-by-step explanation:

Given vectors:

a = [-8, 6]

B = [√7, 3]

θ = ?

To find the angle between the two vectors, we will be using the formula,

                                   a.B = |a||B|cosθ

For simplicity, it is good to first calculate the dot product, and the magnitudes. Then we will substitute the values of the dot product, and the magnitudes of the vectors to solve for the angle.

Calculating the dot product

         a.B = (-8, 6) . (√7, 3)

               = (-8 × √7) + (6 × 3)

               = -8√7 + 18

               = 18 - 8√7

               = 10√7

Calculating the magnitude the vectors

1. The magnitude of vector (-8, 6)    

                |a| = \sqrt{(-8)^{2} + 6^{2}}

                |a| = \sqrt{64 + 36}

                |a| = \sqrt{100}

                |a| = 10

2. The magnitude of vector (√7, 3)

                |B| = \sqrt{(\sqrt{7})^{2} + 3^{2}}

                |B| = \sqrt{7 + 9}

                |B| = \sqrt{16}

                |B| = 4

Calculating the angle between the vectors,

                cosθ = \frac{a.B}{|a||B|}

                cosθ = \frac{10\sqrt{7}}{10 * 4}

                cosθ = 0.6614

                θ = cos⁻¹0.6614

                θ = 48.59°

                θ = 49°

5 0
4 years ago
1-cos(12x)=<br> A. 2sin^2(6x)<br> B. 2cos^2(6x)<br> C. 2cos^2(12x)<br> D. 2sin^2(12x)
Y_Kistochka [10]
Cos(12x) = cos(6x+6x) = cos6xcos6x -sin6xsin6x = cos^2(6x) -sin^2(6x)

1 - cos(12x) = 1 - (cos^2(6x) -sin^2(6x)) = sin^2(6x) +cos^2(6x) - cos^2(6x) +sin^2(6x) = 2sin^2(6x)

so choice A. is right sure 
3 0
3 years ago
Read 2 more answers
I need somebody to hop on my last question i really need help
natita [175]

Ok  ill try but it might be wrong like always

8 0
3 years ago
Read 2 more answers
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