f(x)=2x^2+0x-5
Find the vertex
0/4=0=x
Input x into the equation to find y or f(x)
0+0-5=f(x)
(0,-5) = Vertex
Now find a random x coordinate to input into the equation.
Let's do 4.
32+0-5=f(x)=27
It may not look like a parabola due to it being uneven.
Answer:
5x
Step-by-step explanation:
UwU
37 would be the answer.....
we have
we know that
The radicand must be greater than or equal to zero
so
the domain is is the interval--------> [-2.25,∞)
therefore
<u>the answer is</u>
Answer:
2/3,1,3/2,9/4,27/8
Step-by-step explanation:
f(1)=2/3
f(n)=f(n-1)×3/2
f(2)=f(2-1)×3/2=f(1)×3/2=2/3×3/2=1
f(3)=f(3-1)×3/2=f(2)×3/2=1×3/2=3/2
f(4)=f(4-1)×3/2=f(3)×3/2=3/2×3/2=9/4
f(5)=f(5-1)×3/2=f(4)×3/2=9/4×3/2=27/8
