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katrin2010 [14]
3 years ago
9

ABCD is a trapezium in which AB parallel DC ,DC=30cm and AB=50cm .If X and Y are respectively the mid point of AD and BC then pr

ove that area(DCYX)=7/9 area(XYBA)
Mathematics
1 answer:
Ratling [72]3 years ago
3 0
I have attached the answer. Hope it helps.
Download pdf
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PLEASE HELP and if you can please explain how you got your answer ty
sergey [27]

Answer:

A) Neither

Step-by-step explanation:

If two lines have same slope then they are parallel lines

If slope of line1* slope of line 2 = -1

The the two lines are perpendicular

In this question slope of line = 2\7

Slope of line 2 = 7\2

8 0
3 years ago
Which phrase best describes the relationship indicated by the scatter plot?
Mekhanik [1.2K]

Answer:

negative correlation

Step-by-step explanation:

6 0
4 years ago
Read 2 more answers
Find the values for a and b that would make the equality true.
Crank

Answer:

a = - 4, b = 5

Step-by-step explanation:

Expand the left side and compare the coefficients of like terms on the right side.

- 3(2x² + ax + b)

= - 6x² - 3ax - 3b

Comparing like terms with - 6x² + 12x - 15

x - term → - 3a = 12 ( divide both sides by - 3 )

                    a = - 4

constant term → - 3b = - 15 ( divide both sides by - 3 )

                               b = 5

6 0
3 years ago
Write the equation of a vertical ellipse with a major axis of 20, a minor axis of 12, and a center of (6, 3)
maksim [4K]

Answer:

The equation of a vertical ellipse is  \frac{(x-6)^2}{100} + \frac{(y-3)^2}{36}   = 1\\

Step-by-step explanation:

Here, given:

Length of major axis:  20

⇒ 2 a  = 20  , or , a = 10

Length of minor axis:  12

⇒ 2 b  = 12  , or , b = 6

Also, center (h,k)  = (6,3)

Now, STANDARD EQUATION OF ELLIPSE :

\frac{(x-h)^2}{a^2} + \frac{(y-k)^2}{b^2}   = 1\\

Now, substituting the values, a, b , h and k in above expression, we get:

\frac{(x-6)^2}{10^2} + \frac{(y-3)^2}{6^2}   = 1\\

or, \frac{(x-6)^2}{100} + \frac{(y-3)^2}{36}   = 1\\

Hence, the equation of a vertical ellipse is  \frac{(x-6)^2}{100} + \frac{(y-3)^2}{36}   = 1\\

3 0
3 years ago
I really need help!
xeze [42]
It might be 4 sorry if I’m wrong
5 0
3 years ago
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