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Rus_ich [418]
3 years ago
13

Fill in the missing values in the table for the quadratic function: f(x) = 1/3x^2+1

Mathematics
1 answer:
Vesnalui [34]3 years ago
6 0

Answer:

[x]   f(x)

[-6]  13

[-3]   4

[0]   1

[3]   4

[9]   28

Step-by-step explanation:

f(0) = (1/3)(0^2)+1 = 1

f(3) = (1/3)(3^2)+1 = 4

f(9) = (1/3)(9^2)+1 = 28

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How dose north america achieve 480VAC with 3 pole 120VAC
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Answer:

There are a variety of factors driving the

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Removing the need for a transformer

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The adoption of a 415/240VAC distribution

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Furthermore, while the typical efficiency

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It is this value that often gets overstated by

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distribution to “traditional methods,” as

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Step-by-step explanation:

7 0
3 years ago
A trucking firm has a large inventory of spare parts that have been in storage for a long time. It knowsthat some proportion of
Debora [2.8K]

Answer:

0.1546\leq \widehat{p}\leq 0.3513

Step-by-step explanation:

The firm tests 75 parts, and finds that 0.25 of them are notusable

n = 75

x = 0.25 \times 75 = 18.75≈19

\widehat{p}=\frac{x}{n}

\widehat{p}=\frac{19}{75}

\widehat{p}=0.253

Confidence level = 95%

So, Z_\alpha at 95% = 1.96

Formula of confidence interval of one sample proportion:

=\widehat{p}-Z_\alpha \sqrt{\frac{\widehat{p}(1-\widehat{p}}{n}}\leq \widehat{p}\leq \widehat{p}+Z_\alpha \sqrt{\frac{\widehat{p}(1-\widehat{p}}{n}}

=0.253-(1.96)\sqrt{\frac{0.253(1-0.253)}{75}}\leq \widehat{p}\leq0.253+(1.96)\sqrt{\frac{0.253(1-0.253}{75}}

Confidence interval =0.1546\leq \widehat{p}\leq 0.3513

7 0
4 years ago
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