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Elenna [48]
3 years ago
14

Explain the effect of C on the graph of Y=f(x) for the function y=f(x+c)

Mathematics
1 answer:
irga5000 [103]3 years ago
8 0

f(x) + c -> up by c

f(x) - c -> down by c

f(x + c) -> left by c

f(x - c) -> right by c

For y = f(x + c), the y value of x now takes the y value of the function of x + c, or the one c to the right of x, shifting the entire graph left by c.

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in point form the answer is (32/3 , 6)

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Rise over Run.

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If it's on a line on a graph you count how many it goes up until it's aligned with the next point and then you count how ever many over until it hits it. So it could be 2 up and 4 over making the slope 2/4.

I'm sorry that might not make much sense I'm bad at explaining but let me know if that helps at all!!

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Please help with this math
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676

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3 years ago
Engineers must consider the diameters of heads when designing helmets. The company researchers have determined that the populati
Margaret [11]

Answer:

1. The minimum head breadth that will fit the clientele is of 4.41-in.

2. The maximum head breadth that will fit the clientele is of 7.19-in.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Normally distributed with a mean of 5.8-in and a standard deviation of 0.8-in.

This means that \mu = 5.8, \sigma = 0.8

1. What is the minimum head breadth that will fit the clientele?

The 4.1st percentile, that is, X when Z has a pvalue of 0.041, so X when Z = -1.74.

Z = \frac{X - \mu}{\sigma}

-1.74 = \frac{X - 5.8}{0.8}

X - 5.8 = -1.74*0.8

X = 4.41

The minimum head breadth that will fit the clientele is of 4.41-in.

2. What is the maximum head breadth that will fit the clientele?

100 - 4.1 = 95.9th percentile, that is, X when Z has a pvalue of 0.959, so X when Z = 1.74.

Z = \frac{X - \mu}{\sigma}

1.74 = \frac{X - 5.8}{0.8}

X - 5.8 = 1.74*0.8

X = 7.19

The maximum head breadth that will fit the clientele is of 7.19-in.

8 0
3 years ago
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