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Nostrana [21]
3 years ago
8

A company mixes two kinds of cleansers to get a blend they sell for 59 cents a liter. One of the cleansers costs 50 cents per li

ter, and the other 80 cents per liter. How much of each kind should be mixed to get 2,000 liters of the blend?
Mathematics
1 answer:
lora16 [44]3 years ago
3 0

Answer:

Cleanser that costs 50 cents is 1400 liters, Cleanser that costs 80 cents is 600 liters.

Step-by-step explanation:

We can solve this by using <em>simultaneous equations</em>:

  1. Let us express the question in terms of equations

Let a be cleanser at 50 cents and let b be the cleanser at 80 cents.

Equation 1: 0.5a + 0.8b = 0.59(a+b)

Equation 2: a + b = 2000

From equation 2, a = 2000 - b (Let's call this equation 3)

    2. Substituting equations 2 and 3 in Equation 1:

0.5a + 0.8b = 0.59(a+b)

0.5(2000 - b) + 0.8b = 0.59(2000)

1000 - 0.5b + 0.8b = 1180

0.3b = 180

b = 600

Substitute in equation 3:

a = 2000 - 600

a = 1400

As a note, I formed equation 1 because I know for a fact the cost per liter of a and b. I also know it is sold at 0.59 cents per liter. We are selling 2000 liters in this instance, therefore 0.59(2000) = 1180, which in this case is the selling price.

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Mr. Green teaches mathematics and his class recently finished a unit on statistics. The student scores on this unit are: 40 47 5
Harrizon [31]

Answer:

Mean = 64.46, Median = 62 and Mode = Bi-modal (50 and 62)

Range of the data is 55.

Step-by-step explanation:

We are given that Mr. Green teaches mathematics and his class recently finished a unit on statistics.

<u>The student scores on this unit are:</u>  40, 47, 50, 50, 50, 54, 56, 56, 60, 60, 62, 62, 62, 63, 65, 70, 70, 72, 76, 77, 80, 85, 85, 95.

We know that Measures of Central Tendency are: Mean, Median and Mode.

  • Mean is calculated as;

                   Mean  =  \frac{\sum X}{n}

where  \sum X = Sum of all values in the data

               n = Number of observations = 24

So, Mean  =  \frac{40+ 47+ 50+ 50+ 50+ 54+ 56+ 56+ 60 +60+ 62+ 62+ 62+ 63+ 65+ 70+ 70+ 72+ 76+ 77+ 80+ 85+ 85+ 95}{24}

=  \frac{1547}{24}  =  64.46

So, mean of data si 64.46.

For calculating Median, we have to observe that the number of observations (n) is even or odd, i.e.;

  • If n is odd, then the formula for calculating median is given by;

                     Median  =  (\frac{n+1}{2})^{th} \text{ obs.}

  • If n is even, then the formula for calculating median is given by;

                     Median  =  \frac{(\frac{n}{2})^{th}\text{ obs.} +(\frac{n}{2}+1)^{th}\text{ obs.}   }{2}

Now here in our data, the number of observations is even, i.e. n = 24.

So, Median  =  \frac{(\frac{n}{2})^{th}\text{ obs.} +(\frac{n}{2}+1)^{th}\text{ obs.}   }{2}

                    =  \frac{(\frac{24}{2})^{th}\text{ obs.} +(\frac{24}{2}+1)^{th}\text{ obs.}   }{2}

                    =  \frac{(12)^{th}\text{ obs.} +(13)^{th}\text{ obs.}   }{2}

                    =  \frac{62 + 62  }{2}  =  \frac{124}{2}  =  62

Hence, the median of the data is 62.

  • A Mode is a value that appears maximum number of times in our data.

In our data, there are two values which appear maximum number of times, i.e. 50 and 62 as these both appear maximum 3 times in the data.

This means our data is Bi-modal with 50 and 62.

  • The Range is calculated as the difference between the highest and lowest value in the data.

                      Range  =  Highest value - Lowest value

                                   =  95 - 40 = 55

Hence, range of the data is 55.

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Step-by-step explanation:

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