Kerberos and OpenID are SSO Services.
The code is first declaring array1 as a new array of integers with length 25. Then the comment tells us that somewhere in the middle of the code, values are given to each element of array1.
Lastly, we are iterating through the array using a for loop. We start at index 0, and continue until the index value (a) is one less than the length of the array. So array1[a] will give us the value that was assigned to the element at index a.
In the for loop, we are adding the value of array[a] to the integer "value" which was initialized as 0. Therefore, the result will be the sum of all the integers in array1.
The answers are as follows:
a) F(A, B, C) = A'B'C' + A'B'C + A'BC' + A'BC + AB'C' + AB'C + ABC' + ABC
= A'(B'C' + B'C + BC' + BC) + A((B'C' + B'C + BC' + BC)
= (A' + A)(B'C' + B'C + BC' + BC) = B'C' + B'C + BC' + BC
= B'(C' + C) + B(C' + C) = B' + B = 1
b) F(x1, x2, x3, ..., xn) = ∑mi has 2n/2 minterms with x1 and 2n/2 minterms
with x'1, which can be factored and removed as in (a). The remaining 2n1
product terms will have 2n-1/2 minterms with x2 and 2n-1/2 minterms
with x'2, which and be factored to remove x2 and x'2, continue this
process until the last term is left and xn + x'n = 1
Yes you should install drives first
