The area of a rectangle is 70 square inches and the length of the rectangle is 3 inches longer than the width.

A cold tablet contains the following amounts of active ingredients: acetaminophen 325 mg, chlorpheniramine maleate 2 mg, and dex

kakasveta [241]

Answer:

The number of tablets that can be prepared is 3076.

Step-by-step explanation:

The total amount of active ingredients in the tablet is the sum of the amounts provided in the formula:

$325 mg + 2mg+15 mg=342 mg$

The percentages of each component in the formula are:

Acetaminophen: $\frac{325mg*100}{342mg}=95.03$ %

Chlorpheniramine maleate: $\frac{2mg*100}{342mg} =0.58$ %

Dextromethorphan hydrobromide: $\frac{15mg*100}{342mg}=4.39$ %

If 1 Kg= $10^{6}$ mg of acetaminophen is used, the needed amount of chlorpheniramine maleate would be:

$\frac{10^{6} mg *0.58}{95.03}=6153.85 mg$

Since there are 125 g = 125000 mg of chlorpheniramine maleate, there is enough of these ingredient to run the available acetaminophen out. Thus, the total amount of active ingredients that can be prepared with 1 kg of acetaminophen is:

$\frac{10^{6}mg*100}{95.03}=1052307.7mg$

Since each tablet weighs 342 mg, the number of tablets that can be prepared is:

$\frac{1052307.7mg}{342mg}=3076.923$

Which means that 3076 tablets can be prepared and a there will be a remanent of 0.923*342 mg = 315.69 mg of active ingredients.

7 0

3 years ago

A sandbox in the shape of a rectangular prism is 2 feet deep and 6 feet wide. Filled to the top it can hold 72 cubic feet of san

Sedbober [7]

Answer:

height=6 ft

Step-by-step explanation:

-The volume of a rectangular prism is given by the formula:

$V=lwh$

#We make h the subject of the formula the solve for it:

$V=lwh\\\\\frac{V}{lw}=h\\\\\therefore h=\frac{V}{lw}$

#Substitute to solve for height:

$h=\frac{V}{lw}\\\\=\frac{72}{2\times 6}\\\\=6\ ft$

Hence, the prism has a height of 6 ft.

6 0

2 years ago

Standard Error from a Formula and a Bootstrap Distribution Sample A has a count of 30 successes with and Sample B has a count of

tia_tia [17]

Answer:

Using a formula, the standard error is: 0.052

Using bootstrap, the standard error is: 0.050

Comparison:

The calculated standard error using the formula is greater than the standard error using bootstrap

Step-by-step explanation:

Given

Sample A Sample B

$x_A = 30$ $x_B = 50$

$n_A = 100$ $n_B =250$

Solving (a): Standard error using formula

First, calculate the proportion of A

$p_A = \frac{x_A}{n_A}$

$p_A = \frac{30}{100}$

$p_A = 0.30$

The proportion of B

$p_B = \frac{x_B}{n_B}$

$p_B = \frac{50}{250}$

$p_B = 0.20$

The standard error is:

$SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.30 * (1 - 0.30)}{100} + \frac{0.20* (1 - 0.20)}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.30 * 0.70}{100} + \frac{0.20* 0.80}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.21}{100} + \frac{0.16}{250}}$

$SE_{p_A-p_B} = \sqrt{0.0021+ 0.00064}$

$SE_{p_A-p_B} = \sqrt{0.00274}$

$SE_{p_A-p_B} = 0.052$

Solving (a): Standard error using bootstrapping.

Following the below steps.

Open Statkey
Under Randomization Hypothesis Tests, select Test for Difference in Proportions
Click on Edit data, enter the appropriate data
Click on ok to generate samples
Click on Generate 1000 samples ---- <em>see attachment for the generated data</em>

From the randomization sample, we have:

Sample A Sample B

$x_A = 23$ $x_B = 57$

$n_A = 100$ $n_B =250$

$p_A = 0.230$ $p_A = 0.228$

So, we have:

$SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.23 * (1 - 0.23)}{100} + \frac{0.228* (1 - 0.228)}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.1771}{100} + \frac{0.176016}{250}}$

$SE_{p_A-p_B} = \sqrt{0.001771 + 0.000704064}$

$SE_{p_A-p_B} = \sqrt{0.002475064}$

$SE_{p_A-p_B} = 0.050$

5 0

2 years ago

I NEED HELP ON NUMBER 2 pleaseeee helpppppp

exis [7]

Answer:

Step-by-step explanation:

The slope is -2/4. Don't forget the x!

4 0

3 years ago

Read 2 more answers

I need help with this question so hard

qaws [65]

Answer:

The answer to part B will be for length the mean is 2.08, the median is 2.6, and the mode is 2.6. For height the mean is 1.5, the median is 1.4, and there isn't a mode since no number repeat. It will the 0.6, 1.0, 1.4, 1.7, 2.8. Hope this helps!

Step-by-step explanation:

3 0

2 years ago