Answer:
D. 
and 
.
Step-by-step explanation:
We have been given that one a recent trip, Cindy drove her car 290 miles, rounded to the nearest 10 miles, and used 12 gallons of gasoline, rounded to the nearest gallon.
The range of miles driven would be between 
because number of miles in rounded to nearest 10 miles.
The range of gallons of gasoline would be 
because number of gallons of gasoline in rounded to nearest gallon.
To find mileage, we will divide number of miles by number of gallons.
The possible number of gallons of gasoline will be 12.5 gallons for 285 miles to get the minimum number of miles.
Similarly, the possible number of gallons of gasoline will be 11.5 gallons for 295 miles to get the maximum miles.
Therefore, our required range would be and .
40/2=20
Therefore he can cover 20 miles in 1 hour
Hope this helps!
Answer:
The probability that a container will be shipped even though it contains 2 defectives if the sample size is 88, will be 
Step-by-step explanation:
The first step is to count the number of total possible random sets of taking a sample size of 88 engines over 1212 engines of the population, so ![\left[\begin{array}{ccc}1212\\88\end{array}\right] =1212C88=4.7205x10^{135}](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1212%5C%5C88%5Cend%7Barray%7D%5Cright%5D%20%3D1212C88%3D4.7205x10%5E%7B135%7D)
The second step is to count the number of total possible random sets of taking a sample size of 88 engines over 1210 engines (discounting the 2 defective engines) as the possible ways to succeed, so ![\left[\begin{array}{ccc}1210\\88\end{array}\right] =1212C88=4.0596x10^{135}](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1210%5C%5C88%5Cend%7Barray%7D%5Cright%5D%20%3D1212C88%3D4.0596x10%5E%7B135%7D)
Finally we need to compute 
, therefore the probability that a container will be shipped is
Answer: 100
<u>Step-by-step explanation:</u>
[(25 - 11) + (15 - 9)] * 5
=[ 14 + 6 ] * 5
= 20 * 5
= 100
