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Svetach [21]
3 years ago
13

Can someone solve this -6y-3=3-6y

Mathematics
2 answers:
netineya [11]3 years ago
7 0

Based off of your question, I'll assume you are trying to solve for the "y" variable.

To solve the variable, we need to isolate it by performing opposite operations. However, it's important to remember to perform the operations on both sides of the equal sign so that the equation remains equal

.-6y-3=3-6y

     +3+3

-6y=6-6y

/-6     /-6

y=6+1y

y=y+6

In this case, it looks like we actually have a bit of an odd circumstance. We know that "y" cannot equal "y+ a value," because it simply does not logically make sense.

Therefore, using that logic, we can determine that this equation has no solutions.

Feel free to ask any follow-up questions about this problem using the comment section below!

Svetlanka [38]3 years ago
6 0

Answer:

<h2>No Solution</h2>

Step-by-step explanation:

<h3>Step 1: Add 3</h3>

-6y = 6y

But wait..we have a problem -6y cannot equal 6. We didn't do anything wrong, it is just that this is an invalid equation.

<em>PLEASE MARK BRAINLIEST</em>

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5 0
3 years ago
You buy Apple stock for $120 per share over a period of time the stock value increased at a weekly rate of 5% you sell the stock
Rainbow [258]

Answer:

8.31  weeks

Step-by-step explanation:

Given that the cost of one share of Apple stock, C=$120

Rate is the increment of the stock value, R= 5%/week=0.05 / week.

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Since the stock value increased at 5% every week, so, the interest is compounded weekly, so

S=C\left(1+R\right)^t \\\\ \Rightarrow 180 = 120\left(1+0.05\right)^t \\\\  \Rightarrow 180 = 120\left(1.05 )^t \\\\

\Rightarrow \frac{180}{120}=1.05^t \\\\\Rightarrow 1.5=1.05^t

\Rightarrow \ln(1.5)=t \ln(1.05) [taking log both sides]

\Rightarrow t=\frac {\ln(1.5)}{\ln(1.05)}=8.31 weeks

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6 0
3 years ago
Help me with this, please! Very thankful!
Naya [18.7K]
X. Y
12 —> 4
8 —> 8/3
13 —> 13/3

Substitute x values for y.
y = 1/3(12)
y=4
5 0
2 years ago
Read 2 more answers
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