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OleMash [197]
3 years ago
10

A racing car used 255 litres of fuel to complete a 340 km race.

Mathematics
2 answers:
Lubov Fominskaja [6]3 years ago
5 0
So 255f for 340m. How much for 100m.
255f=340m we need it to be 100m so we devide by 3.4.
255/3.4f=340/3.4m
So 75f=100m
Or the car used 75 liters of fuel for 100 miles.
Nataly [62]3 years ago
4 0
225 litres of fuel for 340 km

225/340 litres of fuel for 1 km

255/340 * 100 litres of fuel for 100 km

2550/34 = 1275/17 litres of fuel per 100 km(simplified)

update:1275/17 = 75 lol 
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andrey2020 [161]

Answer:

(gof) (4) = 9

Hence, option A is true.

Step-by-step explanation:

f(x)=-x³

g(x)=|1/8x -1|

(gof) (4) = g{f(4)}

First wee need to determine f(4)

f(4)=-(4)³

    = -64

so

  (gof) (4) = g{f(4)} = g(-64)

                             =  \left|\frac{1}{8}\left(-64\right)-1\right|

                             =\left|-\frac{1}{8}\cdot \:64-1\right|

                             =\left|-8-1\right|

                             =\left|-9\right|

\mathrm{Apply\:absolute\:rule}:\quad \left|-a\right|=a

                             =9        

Thus,

(gof) (4) = 9

Hence, option A is true.

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2 years ago
Simplify<br> 53<br> Enter your answer in the box
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Answer:

we need more information

Step-by-step explanation:

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3 years ago
Which is a correct first step in solving 5 – 2x &lt; 8x – 3?
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5 < 6x - 3
3 0
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The Choi family bought 6 bags of cookies. Each bag had 15 cookies. They have since eaten 28 of the cookies. How many cookies do
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Answer:

They have 62 cookies left

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3 0
3 years ago
The compressive strength of concrete is normally distributed with mu = 2500 psi and sigma = 50 psi. A random sample of n = 8 spe
ipn [44]

Answer:

The standard error of the sample mean is _17.677_ psi.

Step-by-step explanation:

<u>Explanation</u>:-

A random sample of n = 8 specimens is collected.

Given sample size is n = 8

Given mean of the population 'μ' = 2500 psi

standard deviation 'σ' = 50 psi

Let x⁻ is the mean of the observed sample

Standard error of the sample mean = \frac{S.D}{\sqrt{n} }      ...(i)

Given Population of standard error (S.D) 'σ' = 50 psi

Now substitute all values in (i)

S.E = \frac{50}{\sqrt{8} } =17.677

<u>Conclusion</u>:-

The standard error of the sample mean is _17.677psi.

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