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DochEvi [55]
2 years ago
5

Can someone delete my Question Like A MODERATOR

Mathematics
1 answer:
DochEvi [55]2 years ago
8 0

Answer:

im not moderator

Step-by-step explanation:

dont post a question like this

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I need some answers please please please
8_murik_8 [283]

Answer:

what does slope mean?

4 0
3 years ago
Read 2 more answers
8-1×0+2÷2=? It looks easy, so many different results.
kvasek [131]
You have to use PEMDAS.

8-1*0+2/2 \\  \\ 8-0+2/2 \\  \\ 8-0+1 \\  \\ 8+1 \\  \\ 9
8 0
3 years ago
Read 2 more answers
Using the solubility curve, choose all of the statements that are correct.
irinina [24]

Answer:

See explanation below

Step-by-step explanation:

According to the solubility curve attached, let's analyze each sentence to see which one is correct:

<u>"Solubility of NaCl is least affected by temperature"</u>

True. as you can see in the curve, solubility of NaCl remains almost constant at any value of temperature, so in this case, it does not matter the temperature, the NaCl solubility will be the same.

<u>"completely dissolve 60 g of KBr in 100 g of water at 20 °C"</u>

True. As you can see in the graph, solubility of KBr begins at 60 g, so in 20 °C we have something dissolved there. Actually you have like 70 g dissolved there, so, this is true.

<u>"The solubility of KNO3 is the least affected by changes in temperature"</u>

False. The curve for KNO3 is exponencial, so, changes in temperature do actually affect the solubility.

<u>"100 g of KBr will dissolve completely in 100 g of water at 75 °C"</u>

False. According to the curve, 100 g dissolve when we reach more than 100 °C. At 75 °C only about 85 g of KBr is dissolved.

<u>"if you mix 120 g of NaClO3 in 100 g of water at 10 °C, approximately 30 g will not dissolve"</u>

True. In the graph we can clearly see that at 10 °C only about 90 g is being dissolved so, the rest of the mass is still there as mass.

6 0
3 years ago
What is the equation for the axis of symmetry of the graph of this function?
poizon [28]
F is the anwser:))))))))))
6 0
3 years ago
PLEASE HELP ASAP!!!!!!!!!!!
Serga [27]
8x^2y^{-2}=\dfrac{8x^2}{y^2}\\\\\\\dfrac{8\cdot(-1)^2}{2^2}=\dfrac{8\cdot1}{4}=\dfrac{8}{4}=\boxed{2}

Answer A)
4 0
3 years ago
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