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frosja888 [35]
3 years ago
14

V=pie*r^2*h solve for r

Mathematics
1 answer:
ankoles [38]3 years ago
8 0

Answer:

r = √(V/πh)

Step-by-step explanation:

V=π*r^2*h solve for r

divide both sides by πh

V/πh = π*r^2*h/πh

Simplify

V/πh = r^2

so r = √(V/πh)

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In a sample of 42 water specimens taken from a construction site, 26 contained detectable levels of lead. Construct a 95% conden
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Answer:

The 95% confidence interval for the proportion of water specimens that contain detectable levels of lead is (0.472,0.766).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

In a sample of 42 water specimens taken from a construction site, 26 contained detectable levels of lead.

This means that n = 42, \pi = \frac{26}{42} = 0.619

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So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.619 - 1.96\sqrt{\frac{0.619*0.381}{42}} = 0.472

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.619 + 1.96\sqrt{\frac{0.619*0.381}{42}} = 0.766

The 95% confidence interval for the proportion of water specimens that contain detectable levels of lead is (0.472,0.766).

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3 years ago
Point S is located at -10. Points T and U are each 5 units away from point S. Where are T and U located?
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Answer:

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