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expeople1 [14]
2 years ago
6

What equation represents the proportional relationship displayed in the table? x 2 4 6 8 y 10 20 30 40 Enter your answer by fill

ing in the box to complete the equation. y = x Question 3 (1 point) The graph shows a proportional relationship between the number of kilometers traveled by a bicycle (y) and the number of minutes (x). graph with x axis labeled time in minutes and y axis labeled distanced traveled in kilometers. a line starts at the origin 0 comma 0 and runs through the point 40 comma 12 What is the unit rate, expressed in kilometers per minute? Question 3 options: 0.33 km/min 0.30 km/min 3.10 km/min 3.33 km/min
Mathematics
1 answer:
hjlf2 years ago
5 0

Answer: y=5x

Step-by-step explanation:

pls mark brainliest :)

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I need help please either discord me the answer at F4deG0d#0988 or do it on here cause this is important.
algol13

Answer:

x= 12.5

So

2x = 25

4x = 50

6x = 75

Step-by-step explanation:

line CG is 180 degrees, so 12x + 30 = 180

x = 12.5

7 0
3 years ago
3 ½ – 2 ⅓ <br><br> Give your answer as a improper fraction
andrezito [222]

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6 0
3 years ago
Read 2 more answers
Y=2x-6<br> slope? <br> y- intercept?
krek1111 [17]

Answer:

The slope is 2/1 and the y-intercept is -6.

Step-by-step explanation:

With the y=mx+b formula, m is the slope and b is the intercept.

4 0
3 years ago
Read 2 more answers
Which of the following expressions has the greatest value?
Vilka [71]

Answer:

2^5

Step-by-step explanation:

1^10 = 1 (1*1*1*1*1....)

5^2 = 25 (5*5)

2^5 = 32 (2*2*2*2*2)

3^3 = 27 (3*3*3)

5 0
3 years ago
What are the coordinates of the vertices of the rose garden after a translation two yards east and four yards south? Use the ter
melisa1 [442]

Answer:

The coordinates of the vertices of the original rose garden are A(3, 6), B(3, 3), C(4, 3), and D(4, 6).

Because the rose garden is translated 2 yards east (2 units in the positive x-direction) and 4 yards south (4 yards in the negative y-direction), add 2 units to the x-coordinates and -4 units to the y-coordinates of all the original vertices.

A(3, 6) will become A'[(3 + 2), (6 + (-4))], or A′(5, 2).

B(3, 3) will become B'[(3 + 2), (3 + (-4))], or B′(5, -1).

C(4, 3) will become C'[(4 + 2), (3 + (-4))], or C′(6, -1).

D(4, 6) will become D'[(4 + 2), (6 + (-4))], or D′(6, 2).

8 0
3 years ago
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