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erastovalidia [21]
3 years ago
15

I Promise Brainliest !!!!! Describe how the aperture size relates to the size of the lens opening.

Computers and Technology
2 answers:
sergey [27]3 years ago
8 0

Answer:

As aperture increases in f-stop values, the lens closes. On the other hand, when aperture decreases in f-stop values, the lens opens.

Explanation:<u><em>plz give brainlist</em></u>

barxatty [35]3 years ago
5 0

They both allow the photographer to adjust the amount of light that passes through the lens. To explain in Layman’s terms, an aperture in a camera is like a pupil in the human eye. As you transition between dark and bright environments, the size of your pupil either expands or shrinks accordingly. The same concept can be applied to an aperture. A photographer can enlarge or shrink the size of the aperture to either allow more or little light to reach the sensor of the camera.

The aperture can be described as the size of the lens opening and is made from aperture blades that control the size of the opening (f/stop number). Some typical openings are 3.5, 4.0, and above. As the f/stop number decreases in size and becomes smaller, the opening in the aperture of the lens increases in size and becomes larger. As a result, we get a brighter photograph. However, a larger f/stop number does quite the opposite and as a result, you get a darker photo.

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Create an application containing an array that stores 10 integers. The application should call five methods that in turn (1) dis
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Answer:

  1.     public class Main {
  2.    public static void main(String[] args) {
  3.        int myArray[] = {3, 7, 2, 5, 9,11, 24, 6, 10, 12};
  4.        int myArray2 [] = {1, 2, 3, 4 ,5};
  5.        displayValue(myArray);
  6.        reverseDisplay(myArray);
  7.        displaySum(myArray);
  8.        displayLess(myArray, 10);
  9.        displayHighAvg(myArray);
  10.        displayBoth(myArray, myArray2);
  11.    }
  12.    public static void displayValue(int arr[]){
  13.        for(int i = 0; i < arr.length; i++){
  14.            System.out.print(arr[i] + " ");
  15.        }
  16.        System.out.println();
  17.    }
  18.    public static void reverseDisplay(int arr[]){
  19.        for(int i = arr.length-1; i >= 0; i--){
  20.            System.out.print(arr[i] + " ");
  21.        }
  22.        System.out.println();
  23.    }
  24.    public static void displaySum(int arr[]){
  25.        int sum = 0;
  26.        for(int i = 0; i < arr.length; i++){
  27.            sum += arr[i];
  28.        }
  29.        System.out.println(sum);
  30.    }
  31.    public static void displayLess(int arr[], int limit){
  32.        for(int i = 0; i < arr.length; i++){
  33.            if(arr[i] < limit){
  34.                System.out.print(arr[i] + " ");
  35.            }
  36.        }
  37.        System.out.println();
  38.    }
  39.    public static void displayHighAvg(int arr[]){
  40.        int sum = 0;
  41.        for(int i = 0; i < arr.length; i++){
  42.            sum += arr[i];
  43.        }
  44.        double avg = sum / arr.length;
  45.        for(int i = 0; i < arr.length; i++){
  46.            if(arr[i] > avg){
  47.                System.out.print(arr[i] + " ");
  48.            }
  49.        }
  50.        System.out.println();
  51.    }
  52.    public static void displayBoth(int arr1[], int arr2 []){
  53.        for(int i = 0; i < arr2.length; i++){
  54.            for(int j = 0; j < arr1.length; j++){
  55.                if(arr1[j] == arr2[i]){
  56.                    System.out.print(arr1[j] + " ");
  57.                }
  58.            }
  59.        }
  60.        System.out.println();
  61.    }
  62. }

Explanation:

There are five methods written to solve all the problems stated in the question.

Method 1 : displayValue    (Line 15 - 21)

This is the method that take one input array and use the print() method to display the all the elements in the array.

Method 2: reverseDisplay (Line 23 - 26)

This method will take one input array and print the value in the reverse order. We just need to start with the last index when running the for-loop to print the value.

Method 3: displaySum (Line 31 - 37)

This method will take one input array and use a for-loop to calculate the total of the values in the array.

Method 4: displayLess (Line 39 - 47)

This method will take one two inputs, a array and a limit. We use the limit as the condition to check if any value less than the limit, then the value will only be printed.

Method 5: displayHighAvg (Line 50 - 64)

This method will take one input array and calculate the average. The average will be used to check if any element in the array higher than it, then the value will only be printed.

Method 6: displayBoth  (Line 66 - 75)

This method will take two input arrays and compare both of them to find out if any value appears in both input arrays and print it out.

3 0
3 years ago
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