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Crazy boy [7]
3 years ago
12

8 times the difference between a number and 6 is equal to 4 times the number.

Mathematics
1 answer:
7nadin3 [17]3 years ago
4 0

Answer:

The variable titled "the number" is A: 12.

Step-by-step explanation:

The problem is 8 * (x - 6) = 4 * x

Try the first number as x and rewrite the expression.

8 * (12 - 6) = 4 * 12

Following PEMDAS (the Order of Operations), you need to solve the problem inside the parenthesis.

12 - 6 = 6

Rewrite the problem.

8 * 6 = 4 * 12

8 times 6 is 48.

4 times 12 is 48.

The variable in the expression 8 * (x - 6) = 4 * x is 12.

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The answer is the second option, option B, which is: B. <span>W'(2,8), X'(2,2), Y'(8,2)
</span> The explanation is shown below:
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5 0
3 years ago
What is ? Please help me 1/6x3/1!!!
levacccp [35]

Answer:

1/2

Step-by-step explanation:

1/2

3 0
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If Jk _| lm which statement is true?
nikdorinn [45]
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4 0
3 years ago
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You roll a pair of honest dice. If you roll a total of 7, you win $18; if you roll a total of 11, you win $54; if you roll any o
amm1812
Answer: -1
The negative value indicates a loss

============================================================

Explanation:

Define the three events
A = rolling a 7
B = rolling an 11
C = roll any other total (don't roll 7, don't roll 11)

There are 6 ways to roll a 7. They are
1+6 = 7
2+5 = 7
3+4 = 7
4+3 = 7
5+2 = 7
6+1 = 7
Use this to compute the probability of rolling a 7
P(A) = (number of ways to roll 7)/(number total rolls) = 6/36 = 1/6
Note: the 36 comes from 6*6 = 36 since there are 6 sides per die

There are only 2 ways to roll an 11. Those 2 ways are:
5+6 = 11
6+5 = 11
The probability for event B is P(B) = 2/36 = 1/18

Since there are 6 ways to roll a "7" and 2 ways to roll "11", there are 6+2 = 8 ways to roll either event. 
This leaves 36-8 = 28 ways to roll anything else
P(C) = 28/36 = 7/9

-----------------------------

In summary so far,
P(A) = 1/6
P(B) = 1/18
P(C) = 7/9

The winnings for each event, let's call it W(X), represents the prize amounts.
Any losses are negative values
W(A) = amount of winnings if event A happens 
W(B) = amount of winnings if event B happens
W(C) = amount of winnings if event C happens
W(A) = 18
W(B) = 54
W(C) = -9

Multiply the probability P(X) values with the corresponding W(X) values
P(A)*W(A) = (1/6)*(18) = 3
P(B)*W(B) = (1/18)*(54) = 3
P(C)*W(C) = (7/9)*(-9) = -7

Add up those results
3+3+(-7) = -1

The expected value for this game is -1.
The player is expected to lose on average 1 dollar per game played.


Note: because the expected value is not 0, this is not a fair game.


7 0
3 years ago
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Misha Larkins [42]

Answer:

66763

Step-by-step explanation:

47000*(1+0.105+0.17)+338+6500

5 0
2 years ago
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