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timama [110]
3 years ago
8

During a one-month sales contest, Joaquin sold 56 cars and Annette sold 49 cars. Which ratio is equivalent to the ratio of the n

umber of cars Annette sold to the number of cars Joaquin sold? A. 56:49 B. 3:4 C. 8:7 D. 98:112
Mathematics
2 answers:
julia-pushkina [17]3 years ago
8 0
The answer is 8:7!! When you divide 56:49 by 7 it gives you 8:7 :-)
Verdich [7]3 years ago
5 0

Answer:

D. 98:112

Step-by-step explanation:

We want to find Annette:Joaquin

49:56

Both of these numbers are divisible by 7. so we need to divide both of them by 7.

7: 8

Now multiply by each side by 14

7*14 : 8*14

98: 112

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Hello from MrBillDoesMath!

Answer:

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Discussion:

Let the percent be denoted "p". Then

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2000* p/100 = 160 =>

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Regards,  

MrB


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