Let x,y be two different numbers
suppose x^2=y^2
then x^2-y^2=0
which yields (x+y)(x-y)=0
so either x=y or x=-y
In any case, x and y must be the same value
also when a vairable is squared like y=x^2
we must note that there are 2 possible solutions
x=(+/-)sqrt(y)
Answer:
help me pls the answer is -6
Step-by-step explanation:
Answer:
2/3x
Step-by-step explanation:
This is a simple ax graph. all we need is the slope. the slope is the amount the y goes divided by the amount the x goes. essentially
change in y / change in x
2/3
2/3x
Answer:
Im pretty sure A
Step-by-step explanation:
multiply both sides by 3/4 (reciprocal)
3/4X=pie(r)cubed
divide by pi on both sides
3/4X
-------- = r(cubed)
pi
cube root both sides
Answer:
k12
Step-by-step explanation:
