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kirill115 [55]
3 years ago
13

}^{2} " align="absmiddle" class="latex-formula">
Mathematics
1 answer:
nadya68 [22]3 years ago
8 0
1 Use Product Rule: <span>{x}^{a}{x}^{b}={x}^{a+b}<span><span>x<span><span>​a</span><span>​​</span></span></span><span>x<span><span>​b</span><span>​​</span></span></span>=<span>x<span><span>​<span>a+b</span></span><span>​​</span></span></span></span></span>
<span>{n}^{2+2}<span>n<span><span>​<span>2+2</span></span><span>​​</span></span></span></span>
2 Simplify <span>2+2<span>2+2</span></span> to <span>44</span>
<span><span>{n}^{4}
<span>answer is n<span><span>​4</span><span>​​</span></span></span></span><span>
</span></span>
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i think 300$

Step-by-step explanation:

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Candace has $20 more than Amar. Their combined money totals $95. Write a system of equations represents this situation
STALIN [3.7K]

Answer:

Candace has $57.5 and Amar has $37.5.

Step-by-step explanation:

x+(x+20)=z

x+20=y

x+y=z

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5 0
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omeli [17]

Answer:

Step-by-step explanation:

given is a system of linear equations in 3 variables as

-x - 4y + 2z = −10\\ x + 2y - z = 11 \\x + y - z = 14

This can be represented in matrix form as

AX=B Or

\left[\begin{array}{ccc}-1&-4&2\\1&2&-1\\1&1&-1\end{array}\right] *\left[\begin{array}{ccc}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}-10\\11\\14\end{array}\right]

So solution set

X would be A^{-1} B

|A|=-1(-1)+4(0)+2(-1)=--1

Cofactors of A are

-1    0    -1

-2   -1     -3

0     1      2

So inverse of A is

1    2   0

0   1     -1  

1     3      -2

Solution set would be

x=12

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z=-5

8 0
3 years ago
Help please!!! ty ;D
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Answer:

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90 + 8 ? What are you asking? :)
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3 years ago
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