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Tom [10]
3 years ago
13

Karen wants to estimate the mean number of siblings for each student in her school. She records the number of siblings for each

of 200 randomly selected students in the school. What is the sample?
Mathematics
1 answer:
Tamiku [17]3 years ago
5 0

The sample is 200 randomly selected students.

The following things should be considered:

  • Let us assume the no of siblings for each student be x.
  • Now for determining the mean no of siblings she choose 200 students.

So, here the sample should be 200 randomly selected students.

Therefore the other options should be incorrect.

Thus we can conclude that the sample is 200 randomly selected students.

Learn more about the sample here: brainly.com/question/13287171

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What is the closed linear form of the sequence 3, 4, 5, 6, 7, ...?
Kay [80]

Answer:

Step-by-step explanation:

This is an arith. sequence.

The first term is 3 and the common difference is 1

Thus, the general formula for the nth term of this sequence is:

a(n) = 3 + 1(n - 1)   This matches Answer A

6 0
4 years ago
Read 2 more answers
What is the value of y?<br><br><br><br> Enter your answer in the box.<br><br> y =
Olenka [21]

Answer:

y=40\°

Step-by-step explanation:

we know that

An isosceles triangle has two equal sides and two equal angles

The two equal angles are called the base angles and the third angle is called the vertex angle

In this problem the triangle ABC is an isosceles  triangle

so

AB=AC

5x=40\°

x=8\°

The sum of the internal angles of a triangle is equal to 180\°

so

Find the value of y

(2y+20)\°+2(40\°)=180\°

2y=180\°-20\°-80\°

2y=80\°

y=40\°

6 0
4 years ago
Read 2 more answers
The accompanying data came from a study of collusion in bidding within the construction industry. No. Bidders No. Contracts 2 6
viktelen [127]

Answer:

a)

The proportion of contracts involved at most five bidders is 0.667.

The proportion of contracts involved at least five bidders is 0.51.

b)

The  proportion of contracts involved  between five and 10 inclusive bidders is 0.5.

The  proportion of contracts involved  strictly between five and 10 bidders is 0.304.

Step-by-step explanation:

No. bidders    No. contracts     Relative frequency of contracts

2                         6                       6/102=0.0588

3                         20                     20/102=0.1961

4                         24                     24/102=0.2353

5                         18                       18/102=0.1765

6                         13                        13/102=0.1275

7                          7                          7/102=0.0686

8                          5                          5/102=0.049

9                          6                          6/102=0.0588

10                         2                           2/102=0.0196

11                          1                            1/102=0.0098

Total                  102

a)

We have to find proportion of contracts involved at most five bidders.

Proportion of at most 5= Relative frequency 2+ Relative frequency 3+ Relative frequency 4+ Relative frequency 5

Proportion of at most 5=0.0588+ 0.1961+0.2353+0.1765

Proportion of at most 5=0.6667

The proportion of contracts involved at most five bidders is 0.667.

proportion of at least five bidders= proportion≥5= 1- proportion less than 5

Proportion less than 5=0.0588+ 0.1961+0.2353=0.4902

proportion of at least five bidders=1-0.4902=0.5098

The proportion of contracts involved at least five bidders is 0.51

b)

We have to find proportion of contracts involved  between five and 10 inclusive bidders.

Proportion of contracts between five and 10 inclusive= Relative frequency 5+ Relative frequency 6+ Relative frequency 7+ Relative frequency 8+ Relative frequency 9+ Relative frequency 10

Proportion of between five and 10 inclusive=0.1765 +0.1275 +0.0686 +0.049 +0.0588 +0.0196

Proportion of between five and 10 inclusive=0.5

The  proportion of contracts involved  between five and 10 inclusive bidders is 0.5

We have to find proportion of contracts involved  strictly between five and 10 bidders.

Proportion of contracts strictly between five and 10=  Relative frequency 6+ Relative frequency 7+ Relative frequency 8+ Relative frequency 9

Proportion of strictly between five and 10=0.1275 +0.0686 +0.049 +0.0588

Proportion of strictly between five and 10=0.3039

The  proportion of contracts involved  strictly between five and 10 bidders is 0.304.

8 0
3 years ago
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liraira [26]

Answer:

30 days

Step-by-step explanation:

The common multiples of 15 and 6 are 30, 60, 90 etc and because it increases by 30 each time we can find out that he will play both football and basketball together in thirty days!

8 0
3 years ago
If all city buses carry the same number of passengers, what is the least number of buses needed to carry 710 passengers? 5 10 11
noname [10]

The least number of buses needed to carry 710 passengers is 5.

Option A)5 is the correct answer.

<h3>What is the least number of buses needed to carry 710 passengers? </h3>

Given that;

  • Number of passengers n = 710
  • Least number of buses need B = ?

To get the least number of buses, we say;

Number of buses B = 710 ÷ 150

Number of buses B = 4.7 ≈ 5

The least number of buses needed to carry 710 passengers is 5.

Option A)5 is the correct answer.

Learn to solve more word problems here: brainly.com/question/2610134

#SPJ4

5 0
2 years ago
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