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Nataly [62]
3 years ago
10

Find sec θ if tan θ = 15/8 and θ terminates in QIII.

Mathematics
1 answer:
EastWind [94]3 years ago
5 0
Tangent = opposite/adjacent
tangent = 15 / 8
If opp = 15 and adj = 8 then
hypotenuse^2 = 15^2 + 8^2
hypotenuse^2 = 225 + 64
hypotenuse^2 = 289
hypotenuse = 17

secant = hypotenuse / adjacent
secant = 17 / 8
secant = 2.125

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While mining, Joan found a large metal bar that weighted 40 grams. Joan was able to determine that the bar contained 35% zinc. H
Tpy6a [65]

Answer:

14g zinc

Step-by-step explanation:

To get the mass of zinc in the metal bar, you can multiply the percentage of zinc by the total mass.

40g x .35 = 14g zinc

3 0
3 years ago
WILL MARK BRAINLIEST
dsp73
<h3>Refer to the diagram below</h3>
  1. Draw one smaller circle inside another larger circle. Make sure the circle's edges do not touch in any way. Based on this diagram, you can see that any tangent of the smaller circle cannot possibly intersect the larger circle at exactly one location (hence that inner circle tangent cannot be a tangent to the larger circle). So that's why there are no common tangents in this situation.
  2. Start with the drawing made in problem 1. Move the smaller circle so that it's now touching the larger circle at exactly one point. Make sure the smaller circle is completely inside the larger one. They both share a common point of tangency and therefore share a common single tangent line.
  3. Start with the drawing made for problem 2. Move the smaller circle so that it's partially outside the larger circle. This will allow for two different common tangents to form.
  4. Start with the drawing made for problem 3. Move the smaller circle so that it's completely outside the larger circle, but have the circles touch at exactly one point. This will allow for an internal common tangent plus two extra external common tangents.
  5. Pull the two circles completely apart. Make sure they don't touch at all. This will allow us to have four different common tangents. Two of those tangents are internal, while the others are external. An internal tangent cuts through the line that directly connects the centers of the circles.

Refer to the diagram below for examples of what I mean.

5 0
3 years ago
Three people build a rectangular shed 8 ft wide, 6 ft long, and 7 ft high. How many cubic feet does the shed contain?
dusya [7]
8x6x7= 336
Your answer is 336 ft^3
7 0
3 years ago
What is the third term of the sequence defined by the recursive rule f(1)=3 f(n)=f(n-1)+4
snow_tiger [21]
What is the third term of the sequence defined by the recursive rule f(1)=3 f(n)=f(n-1)+4

Need f(2):

f(2)=f(2-1)+4
f(2)=f(1)+4
f(2)=(3)+4=7

FIND f(3):
f(3)=f(3-1)+4
f(3)=f(2)+4
f(3)=(7)+4
f(3)=11
5 0
3 years ago
Write (1/3i)-(-6+2/3i) as a complex number in standard form
Eddi Din [679]

Answer:

6+\frac{i}{3}

Step-by-step explanation:

\frac{1}{3\imath}-(-6+\frac{2}{3\imath})

\frac{1}{3\imath}+6-\frac{2}{3\imath}

taking like terms together

\frac{1}{3\imath}-\frac{2}{3\imath}+6

taking LCM

\frac{1-2}{3\imath}+6

\frac{-1}{3\imath}+6

taking LCM

\frac{-1+18\imath}{3\imath}

splitting the term

\frac{-1+18\imath}{3\imath}

splitting the term

-\frac{1}{3\imath}+\frac{18\imath}{3\imath}

-\frac{1\times3\imath}{3\imath \times \imath}+6

-\frac{i}{3\imath^2}+6

we know that

\imath^2=-1

putting this value in above equation

\frac{\imath}{3}+6

7 0
3 years ago
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