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navik [9.2K]
3 years ago
15

]solomon needs to justify the formula for the arc length of a sector. which expression best completes this argument? the circumf

erence of a circle is given by the formula c=pi * d , where d is the diameter. because the diameter is twice the radius, c= 2 * pi * r. if equally sized central angles, each with a measure of n°, are drawn, the number of sectors that are formed will be equal to 360°/n° the arc length of each sector is the circumference divided by the number of sectors, or _____. therefore, the arc length of a sector of a circle with a central angle of n° is given by 2*pi*r*n/360 or pi*r*n/180 . a. 2*pi*r/270/n b. 2*pi*r/360/n c. 2*pi*r/180/n d. 2*pi*r/90/n
Mathematics
1 answer:
Anna35 [415]3 years ago
7 0

Answer:

\frac{2 \pi r}{\frac{360^{\circ}}{n^{\circ}}} best completes this argument

Step-by-step explanation:

Circumference of circle =\pi \cdot d

Where d is the diameter of circle

We are given that if equally sized central angles, each with a measure of n°, are drawn, the number of sectors that are formed will be equal to \frac{360^{\circ}}{n^{\circ}}

So, Number of sectors =  \frac{360^{\circ}}{n^{\circ}}

The arc length of each sector is the circumference divided by the number of sectors

\Rightarrow \frac{\pi \cdot d}{\frac{360^{\circ}}{n^{\circ}}}

Diameter d = 2r (r = radius)

\Rightarrow \frac{2 \pi r}{\frac{360^{\circ}}{n^{\circ}}}

Option b is true

Hence\frac{2 \pi r}{\frac{360^{\circ}}{n^{\circ}}} best completes this argument

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let

x-------> total amount of marbles at the beginning


we know that

1) He gave ½ of his marbles plus 1 to Felix

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2)½ of the remaining marbles plus 1 to Ces

(1/2)*[(x-2)/2]+1=[(x-2)/4]+1-----> (x+2)/4 (Ce's marbles)

remaining=[(x-2)/2]-[(x+2)/4]-----> [2x-4-x-2]/4------> (x-6)/4


3) ½ of the last remaining marbles plus 1 to Pedro

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remaining=[(x-6)/4]-[(x+2)/8]------> [2x-12-x-2]/8-----> (x-14)/8


4)If Lito had 1 marble left for himself

so

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Verify

(x+2)/2 (Felix's marbles)------> (22+2)/2=12

(x+2)/4 (Ce's marbles)------> (22+2)/4=6

(x+2)/8 (Pedro's marbles)---> (22+2)/8=3

Lito's marbles------------------> 1

total=12+6+3+1=22--------> is ok


therefore


the answer is

the total amount of marbles at the beginning was 22

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