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2 years ago

Create a word problem using 30+2d as the answer

Mathematics

1 answer:

Tanzania [10]2 years ago

4 0

Answer:

Sonya pays a flat fee of $30 for her phone bill and pays $2 per gigabyte she uses per month. Put Sonya's bill as an equation with d being how many gigabytes she uses per month.

Step-by-step explanation:

We get the flat fee of $30 from "30 + 2d" and the $2 per gigabyte from "30 + 2d" and since we want to find out Sonya's total bill, that's where the + in "30 + 2d" comes from. We want the variable to be d therefore d is how many gigabytes she uses per month.

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The sum of X^2y and (2xy^2 + x^2y) is 6x^2+2xy^2 but what is it? a monomial or a binomial?

o-na [289]

'Tis a Binomial. if it were a monomial, there would be no operator between 6x^2 and 2xy^2

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3 years ago

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The Chevrolet will go farther

Because the Chevy has more gas and miles.

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3 years ago

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The cube root of 5 times the square root of 5 over the cube root of 5 to the 5th power

Fiesta28 [93]

(cube root of 5) * sqrt(5)
--------------------------------- = ?
(cube root of 5^5)

This becomes easier if we switch to fractional exponents:

5^(1/3) * 5^(1/2) 5^(1/3 + 1/2) 5^(5/6)
------------------------ = --------------------- = ------------- = 5^[5/6 - 5/3]
[ 5^5 ]^(1/3) 5^(5/3) 5^(5/3)

Note that 5/6 - 5/3 = 5/6 - 10/6 = -5/6.

1
Thus, 5^[5/6 - 5/3] = 5^(-5/6) = --------------
5^(5/6)

That's the correct answer. But if you want to remove the fractional exponent from the denominator, do this:

1 5^(1/6) 5^(1/6)
---------- * ------------- = -------------- (ANSWER)
5^(5/6) 5^(1/6) 5

7 0

3 years ago

Samples of emissions from three suppliers are classified for conformance to air-quality specifications. The results from 100 sam

tigry1 [53]

Answer:

$P(A) = \frac{30}{100}$

$P(B) = \frac{77}{100}$

$P(A\ n\ B) = \frac{22}{100}$

$P(A\ u\ B) = \frac{85}{100}$

Step-by-step explanation:

Given

See attachment for proper format of table

$n = 100$ --- Sample

A = Supplier 1

B = Conforms to specification

Solving (a): P(A)

Here, we only consider data in sample 1 row.

In this row:

$Yes = 22$ and $No = 8$

So, we have:

$n(A) = Yes + No$

$n(A) = 22 + 8$

$n(A) = 30$

P(A) is then calculated as:

$P(A) = \frac{n(A)}{Sample}$

$P(A) = \frac{30}{100}$

Solving (b): P(B)

Here, we only consider data in the Yes column.

In this column:

$(1) = 22$ $(2) = 25$ and $(3) = 30$

So, we have:

$n(B) = (1) + (2) + (3)$

$n(B) = 22 + 25 + 30$

$n(B) = 77$

P(B) is then calculated as:

$P(B) = \frac{n(B)}{Sample}$

$P(B) = \frac{77}{100}$

Solving (c): P(A n B)

Here, we only consider the similar cell in the yes column and sample 1 row.

This cell is: [Supplier 1][Yes]

And it is represented with; n(A n B)

So, we have:

$n(A\ n\ B) = 22$

The probability is then calculated as:

$P(A\ n\ B) = \frac{n(A\ n\ B)}{Sample}$

$P(A\ n\ B) = \frac{22}{100}$

Solving (d): P(A u B)

This is calculated as:

$P(A\ u\ B) = P(A) + P(B) - P(A\ n\ B)$

This gives:

$P(A\ u\ B) = \frac{30}{100} + \frac{77}{100} - \frac{22}{100}$

Take LCM

$P(A\ u\ B) = \frac{30+77-22}{100}$

$P(A\ u\ B) = \frac{85}{100}$

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3 years ago

What is the reference angle for 7pi/6

DanielleElmas [232]

The reference angle is a positive acute angle. Angle 7π/6 in radians= = 7*180°/6 = 210° ( because π rad=180°).
This angle is in the 3rd Quadrant and formula for the reference angle is:
x-180°.
210°-180°=30°
Answer: The reference angle for 7π/6 is 30°.

3 0

3 years ago

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