Answer:
Given the equation: 
A quadratic equation is in the form: 
where a, b ,c are the coefficient and a≠0 then the solution is given by :
......[1]
On comparing with given equation we get;
a =3 , b = 10
then, substitute these in equation [1] to solve for c;
Simplify:
Also, it is given that the difference of two roots of the given equation is 
i.e,
Here,
, ......[2]
.....[3]
then;
simplify:
or
Squaring both sides we get;
Subtract 100 from both sides, we get
Simplify:
-12c = -96
Divide both sides by -12 we get;
c = 8
Substitute the value of c in equation [2] and [3]; to solve 
or
or
Simplify:
Now, to solve for 
;
or
or
Simplify:
therefore, the solution for the given equation is: 
and -2.
First find the slope of the line connecting these two points:
6-5
m = ------------ = -1/2
-4+2
Substitute this slope into y = mx + b: y = (-1/2)x + b.
Next, subst. 5 for y and -2 for x, and find b:
5 = (-1/2)(-2) + b, or 5-1=b. Then b = 4, and
the equation of the line is y = (-1/2)x + 4.
Answer:
I just finished this in math :) I'm pretty sure it's -3<x<2
Answer:
Step-by-step explanation:
We have been given the zeroes of polynomial which are -1,2,7
That means the factors are (x+1) (x-2) (x-7)
When we want to a polynomial from zeroes we multiply the factors
Hence, the required polynomial is:
