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3 years ago

Which of the following statements about JK and JL is true?

Mathematics

1 answer:

bulgar [2K]3 years ago

5 0

Answer:

Step-by-step explanation:

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grandymaker [24]

Answer:

0.375 pages per minute.

Step-by-step explanation:

6 0

3 years ago

What is 64% out of 150?

motikmotik

64 x

----- = ------

100 150

100x = 9600

x = 96

8 0

3 years ago

Read 2 more answers

Melanies blue notebook cover is 20 centimeters by 30 centimeters. She has a sticker for each letter in her name. Each sticker is

gizmo_the_mogwai [7]

Find the surface area of her notebook.

30 + 30 + 20 + 20 = 100

Now find the surface area of the square stickers.

2 + 2 + 2 + 2 = 8

So this is the surface area of one square, now multiply it by 8.

8 * 7 = 56

This is the surface area of all the stickers, now subtract it to the surface area of the notebook:

100 - 56 = 44

So 44 centimeters of the notebook cover will still be showing.

4 0

3 years ago

Problem 4: Solve the initial value problem

pishuonlain [190]

Separate the variables:

$y' = \dfrac{dy}{dx} = (y+1)(y-2) \implies \dfrac1{(y+1)(y-2)} \, dy = dx$

Separate the left side into partial fractions. We want coefficients a and b such that

$\dfrac1{(y+1)(y-2)} = \dfrac a{y+1} + \dfrac b{y-2}$

$\implies \dfrac1{(y+1)(y-2)} = \dfrac{a(y-2)+b(y+1)}{(y+1)(y-2)}$

$\implies 1 = a(y-2)+b(y+1)$

$\implies 1 = (a+b)y - 2a+b$

$\implies \begin{cases}a+b=0\\-2a+b=1\end{cases} \implies a = -\dfrac13 \text{ and } b = \dfrac13$

So we have

$\dfrac13 \left(\dfrac1{y-2} - \dfrac1{y+1}\right) \, dy = dx$

Integrating both sides yields

$\displaystyle \int \dfrac13 \left(\dfrac1{y-2} - \dfrac1{y+1}\right) \, dy = \int dx$

$\dfrac13 \left(\ln|y-2| - \ln|y+1|\right) = x + C$

$\dfrac13 \ln\left|\dfrac{y-2}{y+1}\right| = x + C$

$\ln\left|\dfrac{y-2}{y+1}\right| = 3x + C$

$\dfrac{y-2}{y+1} = e^{3x + C}$

$\dfrac{y-2}{y+1} = Ce^{3x}$

With the initial condition y(0) = 1, we find

$\dfrac{1-2}{1+1} = Ce^{0} \implies C = -\dfrac12$

so that the particular solution is

$\boxed{\dfrac{y-2}{y+1} = -\dfrac12 e^{3x}}$

It's not too hard to solve explicitly for y; notice that

$\dfrac{y-2}{y+1} = \dfrac{(y+1)-3}{y+1} = 1-\dfrac3{y+1}$

Then

$1 - \dfrac3{y+1} = -\dfrac12 e^{3x}$

$\dfrac3{y+1} = 1 + \dfrac12 e^{3x}$

$\dfrac{y+1}3 = \dfrac1{1+\frac12 e^{3x}} = \dfrac2{2+e^{3x}}$

$y+1 = \dfrac6{2+e^{3x}}$

$y = \dfrac6{2+e^{3x}} - 1$

$\boxed{y = \dfrac{4-e^{3x}}{2+e^{3x}}}$

7 0

2 years ago

The average length of a King Cobra is 118 inches, which is 22 inches longer than the black mamba. Write and solve an addition eq

TiliK225 [7]

I think it would be:

22 + x = 118 for your equation.

And then to solve, it would be:

22 + x = 118
-22 -22

x = 96

Average length of black mamba = 96 inches

However it is late where I am so my bad if that’s not what you needed

4 0

3 years ago