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Alekssandra [29.7K]
3 years ago
7

In the following calculation, which part should be calculated first? 3 + (2 * 4) - 5 / 2

Mathematics
2 answers:
meriva3 years ago
8 0

Always solve the parenthese first

Nataliya [291]3 years ago
4 0
Basing from pemdas, begin with parentheses.
(2*4) should be calculated first
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A company sells boxes of duck calls (d) for $35 and boxes of turkey calls (t) for $45. they make batches of duck calls that fill
SIZIF [17.4K]

Answer:

Option A is the correct choice.

Step-by-step explanation:

Let d be the number of boxes of duck calls and t be the number of boxes of turkey calls.

We have been given that a company sells boxes of duck calls for $35 and boxes of turkey calls (t) for $45, so the revenue earned from selling d boxes of duck and t boxes of turkey call will be 35d and 45t respectively.

Further, the company plan to make $300. We can represent this information as:

35d+45t=300...(1)

We are also told that they make batches of duck calls that fill 6 boxes and batches of turkey calls that fill 8 boxes. the company only has 42 boxes. We can represent this information as:

6d+8t=42...(2)

6d=42-8t...(2)

Therefore, our desired system of equation will be:

35d+45t=300...(1)

6d=42-8t...(2)  


8 0
3 years ago
Need help to answer please
NNADVOKAT [17]

Answer:

0I do not know

Step-by-step explanation:

you good post on this post y el que me and the en el mundo del abecedario y la música que ✨ 7th en is the trail from a 6th street in

6 0
3 years ago
Prove that the sum of the squares of any two odd numbers is always even
ValentinkaMS [17]

Answer:

proof below

Step-by-step explanation:

Remember that a number is even if it is expressed so n = 2k. It is odd if it is in the form 2k + 1 (k is just an integer)

Let's say we have to odd numbers, 2a + 1, and 2b + 1. We are after the sum of their squares, so we have (2a + 1)^2 + (2b + 1)^2. Now let's expand this;

(2a + 1)^2 + (2b + 1)^2 = 4a^2 + 4a + 4b + 4b^2 + 4b + 2

= 2(2a^2 + 2a + 2b^2 + 2b + 1)

Now the sum in the parenthesis, 2a^2 + 2a + 2b^2 + 2b + 1, is just another integer, which we can pose as k. Remember that 2 times any random integer, either odd or even, is always even. Therefore the sum of the squares of any two odd numbers is always even.

6 0
3 years ago
Point Tis on line segment SU. Given TU = 4x + 1, SU = 8, and ST = 3x,
Harrizon [31]

Answer:

5 units

Step-by-step explanation:

If point T is on the line segment SU, then ST + TU = SU.

Given

TU = 4x + 1

SU = 8

ST =  3x

To get TU, we need to get the value of x first. To get x, we will substitute the given parameters into the formula;

3x+4x+1 = 8

7x+1 = 8

subtract 1 from both sides

7x+1-1 = 8-1

7x = 7

divide both sides by 7

7x/7 = 7/7

x = 1

Substitute x = 1 into the length TU

Since TU = 4x+1

TU = 4(1)+1

TU = 5

Hence the numerical length of TU is 5 units

4 0
3 years ago
SOMEONE HELP,FAST!!!!!!Solve.then round to the nearest hundred.23.70 divided by 1.8
Daniel [21]

Answer: 0

Step-by-step explanation:

23.70/1.8 = 13.16666....

Rounding to the nearest hundred is 0, because 13 is less than 50.

8 0
3 years ago
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