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Katen [24]
3 years ago
8

Determine algebraically whether the given function is even, odd, or neither.

Mathematics
1 answer:
uranmaximum [27]3 years ago
7 0
To check whether a function is odd or even, we simply substitute the argument by its negative version, namely "x" by "-x".

if the expression simplifies to resemble the original expression, that simply means the expression is even.  If it resembles the original negative expression, is odd.

\bf g(x)=-2x^3-9\\\\
-------------------------------\\\\
\stackrel{x=-x}{g(-x)}=-2(-x)^3-9\implies g(-x)=-2(-x)(-x)(-x)-9
\\\\\\
g(-x)=+2(x)(x)(x)-9\implies g(-x)=2x^3-9

 well, that doesn't look like the original - 2x³ - 9, so is not even.

and -f(x) would be 2x³ + 9, and that doesn't look like either, so is not odd.

thus is neither.
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kodGreya [7K]

Answer: 7\times10^{19} buckets

Step-by-step explanation:

Given:  A cubic kilometer=10^{15}cubic centimeters

The volume of  world’s oceans=1.4\times10^{9} cubic kilometers of water.

⇒ The volume of  world’s oceans=1.4\times10^{9}\times10^{15} cubic centimeters of water.

Volume of a bucket = 20,000 cubic centimeters of water.

The number of bucket-loads would it take to bucket out the world’s oceans

n=\frac{\text{volume of ocean}}{\text{volume of bucket}}=\frac{1.4\times10^{9}\times10^{15}}{20000}

\Rightarrow\ n=\frac{1.4\times10^{9+15}}{0.2\times10^5}......[a^n\times a^m=a^{m+n}]\\\Rightarrow\ n=7\times10^{24-5}.....[\frac{a^m}{a^n}=a^{m-n}]\\\Rightyarrow\ n=7\times10^{19}

hence,  7\times10^{19} bucketloads would it take to bucket out the world’s oceans.

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3 years ago
When using blocking to deal with extraneous factors in an experiment, the
Elena L [17]

Answer:

<em>False</em>

Step-by-step explanation:

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Step-by-step explanation:

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<em>mass</em><em> </em><em>is</em><em> </em><em>2kg</em>

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uysha [10]

Answer: -1/2, -0.22, 0, 12%, 0.56

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12% is equivalent to 0.12, meaning it is more than 0, and less than 0.56, which is the greatest number.

0.56 has more value than any other number in the problem, meaning it goes last in the order.

8 0
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