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lilavasa [31]
3 years ago
12

What is the greatest common factor of 6c^2 and 10c^3

Mathematics
1 answer:
Art [367]3 years ago
6 0
6c^2 
10c^3

GCF - 2c

hope you understand
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how to transform the quantity of the fifth root of x to the seventh power, to the third power into an expression with a rational
Maurinko [17]
\bf a^{\frac{{ n}}{{ m}}} \implies  \sqrt[{ m}]{a^{ n}} \qquad \qquad
\sqrt[{ m}]{a^{ n}}\implies a^{\frac{{ n}}{{ m}}}\\\\
-----------------------------\\\\
\sqrt[5]{(x^7)^3}\implies \sqrt[5]{x^{7\cdot 3}}\implies \sqrt[5]{x^{21}}\implies x^{\cfrac{}{}\frac{21}{5}}
8 0
3 years ago
Read 2 more answers
Write an equation in slope-intercept form for the 2 points (-2,2) and (2,-2)
Hoochie [10]

Answer:

y=-x

Step-by-step explanation:

Plug (-2,2) for y= mx+b (2=m(-2) + b)

Plug (2,-2) for y=mx +b (-2=m(2) +b)

Causing them to turn into a system of equations for y= -x

6 0
3 years ago
Malcolm is driving 1, 273 miles from Wichita to Charleston for a family reunion. He drives 418 miles the first day and 384 miles
zhuklara [117]

Answer:

Step-by-step explanation:

418 to the nearest ten is 420

384 to the nearest ten is 380

1273 to the nearest ten is 1270

1270-(420+380)=1270-800=470 miles

7 0
3 years ago
1/2 x + 3 = 15 what is the x
sergey [27]

Answer:

x=24

Step-by-step explanation:

x/2+3=15

-3 both sides

x/2=15−3

15-3=12

x/2=12

12*2=24

x=24

6 0
3 years ago
Read 2 more answers
Solve the system by the substitution method.
Gemiola [76]

Answer:

(2,2)

Step-by-step explanation:

Given equations

x-3y=-4-------------------------------(1)

y=-3x+8.------------------------------(2)

Substitute 2 in 1. This means use the value of y in equation 1, to replace y

x-3(-3x+8)=-4------------------open brackets

x+9x-24=-4---------------------collect like terms

10x=-4+24

10x=20---------------------------divide by 10 both sides to get value of x

10x/10=20/10=2

x=2------------------------------use value of x in equation (2) to get value of y

y=-3x+8

y=-3(2)+8

y=-6+8=2

solutions

x=2, y=2

7 0
4 years ago
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