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VARVARA [1.3K]
2 years ago
7

Pls help me solve this​

Mathematics
1 answer:
Elodia [21]2 years ago
8 0
Volume = Area of triangle x length


Area of triangle = 1/2 x base x height

Area of triangle = 1/2 x 5 x 4

Area of triangle = 10


Volume = area of triangle x length

Volume = 10 x 12

Volume = 120 cm^3
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How to turn negative into mixed numbers into improper fractions
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- 2 2/3.....temporarily disregard the negative sign......take ur whole number (2) and multiply it by ur denominator (3) giving u 6, then add that to ur numerator (2) giving u 8....then put that number over the original denominator (3) giving u 8/3...and then put back ur negative sign...-8/3
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How many different numbers can you make out of 1,2,3 and they can't have two of the same numbers in 1 problem ( can't be decimal
Zigmanuir [339]
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slot method

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6 0
3 years ago
(x+y)^2 (x2+2xy+y2) pleas show all work
lakkis [162]

Answer:

{x}^{4}+4{x}^{3}y+6{x}^{2}{y}^{2}+4x{y}^{3}+{y}^{4}x

​4

​​ +4x

​3

​​ y+6x

​2

​​ y

​2

​​ +4xy

​3

​​ +y

​4

​​  

Step-by-step explanation:

1 Use Square of Sum: {(a+b)}^{2}={a}^{2}+2ab+{b}^{2}(a+b)

​2

​​ =a

​2

​​ +2ab+b

​2

​​ .

({x}^{2}+2xy+{y}^{2})({x}^{2}+2xy+{y}^{2})(x

​2

​​ +2xy+y

​2

​​ )(x

​2

​​ +2xy+y

​2

​​ )

2 Expand by distributing sum groups.

{x}^{2}({x}^{2}+2xy+{y}^{2})+2xy({x}^{2}+2xy+{y}^{2})+{y}^{2}({x}^{2}+2xy+{y}^{2})x

​2

​​ (x

​2

​​ +2xy+y

​2

​​ )+2xy(x

​2

​​ +2xy+y

​2

​​ )+y

​2

​​ (x

​2

​​ +2xy+y

​2

​​ )

3 Expand by distributing terms.

{x}^{4}+2{x}^{3}y+{x}^{2}{y}^{2}+2xy({x}^{2}+2xy+{y}^{2})+{y}^{2}({x}^{2}+2xy+{y}^{2})x

​4

​​ +2x

​3

​​ y+x

​2

​​ y

​2

​​ +2xy(x

​2

​​ +2xy+y

​2

​​ )+y

​2

​​ (x

​2

​​ +2xy+y

​2

​​ )

4 Expand by distributing terms.

{x}^{4}+2{x}^{3}y+{x}^{2}{y}^{2}+2{x}^{3}y+4{x}^{2}{y}^{2}+2x{y}^{3}+{y}^{2}({x}^{2}+2xy+{y}^{2})x

​4

​​ +2x

​3

​​ y+x

​2

​​ y

​2

​​ +2x

​3

​​ y+4x

​2

​​ y

​2

​​ +2xy

​3

​​ +y

​2

​​ (x

​2

​​ +2xy+y

​2

​​ )

5 Expand by distributing terms.

{x}^{4}+2{x}^{3}y+{x}^{2}{y}^{2}+2{x}^{3}y+4{x}^{2}{y}^{2}+2x{y}^{3}+{y}^{2}{x}^{2}+2{y}^{3}x+{y}^{4}x

​4

​​ +2x

​3

​​ y+x

​2

​​ y

​2

​​ +2x

​3

​​ y+4x

​2

​​ y

​2

​​ +2xy

​3

​​ +y

​2

​​ x

​2

​​ +2y

​3

​​ x+y

​4

​​  

6 Collect like terms.

{x}^{4}+(2{x}^{3}y+2{x}^{3}y)+({x}^{2}{y}^{2}+4{x}^{2}{y}^{2}+{x}^{2}{y}^{2})+(2x{y}^{3}+2x{y}^{3})+{y}^{4}x

​4

​​ +(2x

​3

​​ y+2x

​3

​​ y)+(x

​2

​​ y

​2

​​ +4x

​2

​​ y

​2

​​ +x

​2

​​ y

​2

​​ )+(2xy

​3

​​ +2xy

​3

​​ )+y

​4

​​  

7 Simplify.

{x}^{4}+4{x}^{3}y+6{x}^{2}{y}^{2}+4x{y}^{3}+{y}^{4}x

​4

​​ +4x

​3

​​ y+6x

​2

​​ y

​2

​​ +4xy

​3

​​ +y

​4

​​  

7 0
3 years ago
Read 2 more answers
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