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melisa1 [442]
3 years ago
12

Please help me guys, its five questions

Mathematics
1 answer:
ruslelena [56]3 years ago
7 0

Answer:

1. A 2.d 3.b 4.a 5. c

Step-by-step explanation:

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WILL GIVE BRAINLIST SOON AS I CAN SOMEBODY PLEASE HELP ME ​
fgiga [73]

Answer:

A= 75.06 Sq Cm

Step-by-step explanation:

Please refer to the picture attached with this.

In ΔABD

AB = 8.5 , AD = 6 and say BD = x

Applying Pythagoras theorem in this triangle

Pythagoras theorem says

a^2+b^2=c^{2}

where c is the side opposite to the right angle, and b and a are the other two sides of the right angled triangle.

x^2+6^2=8.5^{2}

x^2=72.25-36

x^2=36.25

x=6.02

Hence side a = x +19

a = 6.02+19

a = 25.02

Now we apply the formula for area of a triangle which is given as

A=\frac{1}{2}\times b \times h

Where b is the base , here we have base as a = 25.02

h is the height , here h = 6

Putting these values in Formula we get

A=\frac{1}{2}\times 25.02 \times 6

A= 25.02 \times 3

A=75.06

Hence Area of the triangle is 75.06 sq cm

5 0
3 years ago
Help!! Answer !!! about to run out of time in test!!
Gemiola [76]

\qquad \qquad\huge \underline{\boxed{\sf Answer}}

Here's the solution ~

Let's find the measure of hypotenuse first, by using Pythagoras theorem ;

\qquad \sf  \dashrightarrow \: h {}^{2}  =  {8}^{2}  +  {6}^{2}

\qquad \sf  \dashrightarrow \: h {}^{2}  =  {36}^{}  +  {64}^{}

\qquad \sf  \dashrightarrow \: h {}^{2}  = 100

\qquad \sf  \dashrightarrow \: h {}^{}  =  \sqrt{100}

\qquad \sf  \dashrightarrow \: h {}^{}  =  {10}

Now, let's find the asked values ~

\qquad \sf  \dashrightarrow \:  \sin(x) =  \dfrac{opposite \: side}{hypotenuse}

\qquad \sf  \dashrightarrow \:  \sin(x) =  \dfrac{6}{10}

\qquad \sf  \dashrightarrow \:  \sin(x) =  \dfrac{3}{5}   \: or \: 0.6 \: units

For Cos y :

\qquad \sf  \dashrightarrow \:  \cos(y) =  \dfrac{adjcant \: side}{hypotenuse}

\qquad \sf  \dashrightarrow \:  \cos(y)   = \dfrac{6}{10}

\qquad \sf  \dashrightarrow \:  \cos(y)   = \dfrac{3}{5}  \: or \: 0.6 \: units

As we can see that both sin x and Cos y have equal values, therefore The required relationships is equality.

I.e Sin x = Cos y

Hope it helps ~

3 0
3 years ago
What is the area of the rectangle<br> below?
DiKsa [7]

Answer:

Area of rectangle = l×b= 3 1/4 × 1 1/2

= 31/8 = 4 7/8

4 0
2 years ago
$14,038 is invested, part at 14% and the rest at 12%. If the interest earned from the amount invested at 14% exceeds the interes
Advocard [28]

Answer:

492.99

Step-by-step explanation: x = amount invested at 12%

y = amount invested at 9%

---

x + y = 20287

0.12x = 0.09y + 492.99

---

put the system of linear equations into standard form

---

x + y = 20287

0.12x - 0.09y = 492.99

5 0
3 years ago
What is the equation of the line that is perpendicular to the given line and has an x-intercept of -3?
Anvisha [2.4K]

Answer:

y=-\frac{3}{2}x-\frac{9}{2}

Step-by-step explanation:

Let the equation of the perpendicular line is,

y = mx + b

where m = slope of the line

b = y-intercept

From the graph, slope of the line passing through (0, -1) and (3, 1),

m' = \frac{y_2-y_1}{x_2-x_1}

m' = \frac{1+1}{3-0}

m' = \frac{2}{3}

To get the slope (m) of this line we will use the property of perpendicular lines,

m × m' = (-1)

m × \frac{2}{3} = -1

m = -\frac{3}{2}

Equation of the perpendicular line will be,

y=-\frac{3}{2}x+b

x-intercept of the line is (-3) therefore, point on the line is (-3, 0)

0 = -\frac{3}{2}(-3)+b

b = -\frac{9}{2}=-4.5

Equation of the line will be,

y=-\frac{3}{2}x-\frac{9}{2}

3 0
3 years ago
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