Answer:
y=3
Step-by-step explanation:
y=mx+b where m = slope and b=y-intercept
slope: 0, y-intercept: 3
y=(0)x + 3
y=3
We can use the points (2, -2) and (4, -1) to solve.
Slope formula: y2-y1/x2-x1
= -1-2/4-(-2)
= -3/6
= -1/2
Point slope form: y - y1 = m(x - x1)
y - 2 = -1/2(x + 2)
Solve for y-intercept.
-2 = -1/2(2) + b
-2 = -1 + b
-2 + 1 = -1 + 1 + b
-1 = b
Slope Intercept Form: y = mx + b
y = -1/2x - 1
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Wolfyy :)
Answer:
x = -2
Step-by-step explanation:
The tangent line has length "x + 8"
The secant line has length "x + 6 + 5", where
5 is the inner part
x + 6 is the outer part
Now,
the secant-tangent theorem tells us that square of the tangent line is equal to the outer segment of secant line multiplied by length of whole secant line.
So, we can say:

We can solve for x shown below:

The value of x is -2
The y intercept of this function is always (0, a).
This is because when we place 0 in for x (which is the only way it'll be on the y-axis, we get 'a' as a result. This is because of the rule that raising anything to the 0th power will result in the number 1 and multiplying anything by 1 gives us the same number. See the work below for the example.
F(x) = a*b^x
F(0) = a*b^0
F(0) = a*1
F(0) = a
And for an example with a random number, we'll use a = 5 and b = 3
F(x) = 5*3^x
F(0) = 5*3^0
F(0) = 5*1
F(0) = 5
No matter what a and b equal, the intercept will be the a value.
Answer:
positve and negative i think
Step-by-step explanation: