$\dfrac{10x^6y^3+20x^3y^2}{5x^3y}=\dfrac{(5x^3y)(2x^3y^2)+(5x^3y)(4y)}{5x^3y}\\\\=\dfrac{5x^3y(2x^3y^2+4y)}{5x^3y}\qquad\text{cancel}\ 5x^3y\\\\=2x^3y^2+4y$

8 0

3 years ago

Please help! Will give branliest for correct answer ! God Bless uu!!

mafiozo [28]

Answer:

Solution given:.

area of traingle EFG=1/2b×h=1/2×7×6=21cm²

area of rectangle ABCD=l×b=(20+9)×7=203cm²

area of rectangle BHIJ=l×b=9×11=99cm²

Total area =21+203+99=323cm² is a required answer

8 0

3 years ago

Read 2 more answers

Consider the matrix. What is the value of |C|?

garri49 [273]

Answer:

-3

Step-by-step explanation:

6 0

3 years ago