<h2><em><u>
Answer:</u></em></h2><h2><em><u>
Sorry i didn't understand the question but thank you for the points </u></em></h2><h2><em><u>
Step-by-step explanation:</u></em></h2>
<em><u></u></em>
<span>For given hyperbola:
center: (0,0)
a=7 (distance from center to vertices)
a^2=49
c=9 (distance from center to vertices)
c^2=81
c^2=a^2+b^2
b^2=c^2-a^2=81-49=32
Equation of given hyperbola:
..
2: vertices (0,+/-3) foci (0,+/-6)
hyperbola has a vertical transverse axis
Its standard form of equation: , (h,k)=(x,y) coordinates of center
For given hyperbola:
center: (0,0)
a=3 (distance from center to vertices)
a^2=9
c=6 (distance from center to vertices)
c^2=36 a^2+b^2
b^2=c^2-a^2=36-9=25
Equation of given hyperbola:
</span>
Answer: is that a high school math it looks hard to me
Step-by-step explanation??
Answer:
5 1/10 meters
Step-by-step explanation:
18 4/5 can be changed to 18 8/10 so
18 8/10 - 13 7/10 = 5 1/10 meters
Answer:
Step-by-step explanation:
Complete Question:
Chapter 6, Section 1-D, Exercise 009 Is a Normal Distribution Appropriate? In each case below, is the sample size large enough so that the sample proportions follow a normal distribution?
a) n=600 p=0.2
b) n=20, p=0.4
if np=10 and npq=10 then the data follows normal distribution
a) np= 120,
q= 1-0.2= 0.8
npq= 600 ×0.2×0.4 = 48
Normal distribution is appropriate and sample size is large enough
b) np= 8
q= 1-0.4= 0.6
npq= 20 × 0.4×0.6= 4.8
sample size is not large enough so normal distribution is not appropriate.
