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vivado [14]
3 years ago
13

What is the value of the digit 5 in the number 225,673.

Mathematics
2 answers:
Tresset [83]3 years ago
7 0

Hello!

To find the value of a digit, we must first look at its place value. When you're given a number, the place value of the number on the furthest right is 1, and for each number you move left, the place value increases by 10 times.

We're given the number 225,673. If we follow this rule, we see the place value of 3 is 1, 7 is 10, 6 is 100, and 5 is 1000.

Since we know that, we now know that there are 5 1,000s, which would make 5,000.

Therefore, your answer is 5,000.

Hope this helps!

Natasha_Volkova [10]3 years ago
6 0
The value of the digit 5 is 5,000.
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Pls help I dont know how to do this​
german

Answer:

  • 1. CE = 63
  • 2. x = 16

Step-by-step explanation:

Use proportions to solve.

Corresponding sides have same ratio.

<u>Question 1</u>

  • DE/EG = CE/EF
  • (6x + 3)/17 = (8x - 1)/21
  • 21(6x + 3) = 17(8x - 1)
  • 126x + 63 = 136x - 17
  • 10x = 80
  • x = 8
  • CE = 8*8 - 1
  • CE = 63

<u>Question 2</u>

  • KM/MD = KZ/ZH
  • (x + 8)/21 = 32/28
  • x + 8 = 21*8/7
  • x + 8 = 24
  • x = 24 - 8
  • x = 16
5 0
3 years ago
Find the correct plugged in formula for each figure.
r-ruslan [8.4K]

Answer:

3

Step-by-step explanation:

I'm just guessing because you don't give any numbers or anything at all

4 0
2 years ago
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The circle passes through the point (-1,-6). What is its radius?
love history [14]

Answer:

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3 0
3 years ago
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How many solutions does this system have? y=3/4x-5 -3x+4y=-20?
lisov135 [29]

Answer:

infinite

Step-by-step explanation:

If you multiply all factors in the secon eqation by 4, you will get the first eqation.

Therefore for any value of x you can find y, thus having an infinite number of x,y pairs

8 0
3 years ago
Forces of 9 lbs and 13 lbs act at a 38º angle to each other. Find the magnitude of the resultant force and the angle that the re
fiasKO [112]

Answer: R=20.84\ lb\quad 22.57^{\circ},15.43^{\circ}

Step-by-step explanation:

Given

Two forces of 9 and 13 lbs acts 38^{\circ} angle to each other

The resultant of the two forces is given by

\Rightarrow R=\sqrt{a^2+b^2+2ab\cos \theta}

Insert the values

\Rightarrow R=\sqrt{9^2+13^2+2(9)(13)\cos 38^{\circ}}\\\Rightarrow R=\sqrt{81+169+184.394}\\\Rightarrow R=\sqrt{434.394}\\\Rightarrow R=20.84\ lb

Resultant makes an angle of

\Rightarrow \alpha=\tan^{-1}\left( \dfrac{b\sin \theta}{a+b\cos \theta}\right)\\\\\text{Considering 9 lb force along the x-axis}\\\\\Rightarrow \alpha =\tan^{-1}\left( \dfrac{13\sin 38^{\circ}}{9+13\cos 38^{\circ}}\right)\\\\\Rightarrow \alpha =\tan^{-1}(\dfrac{8}{19.244})\\\\\Rightarrow \alpha=22.57^{\circ}

So, the resultant makes an angle of 22.57^{\circ} with 9 lb force

Angle made with 13 lb force is 38^{\circ}-22.57^{\circ}=15.43^{\circ}

7 0
3 years ago
Read 2 more answers
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