Answer:
x = 10
Step-by-step explanation:
In the last step, you can see that the fraction 
has been multiplied by its reciprocal 
, making it cancel out. The reciprocal has been multiplied to both sides, so all you need to do is multiply 
· :
6 · 5 = 30
3 · 1 = 3
<u><em>So now you should have the fraction:</em></u>
x = 
<u><em>But, you can still simplify the fraction by dividing 30 by 3:</em></u>
x = 10
The answer is 28. 7x2=14 and then 14x2=28. Remember PEMDAS
Answer: tea = 15 rupees per kg
sugar= 3 rupees per kg
Step-by-step explanation:
Hi, to answer this question we have to write a system of equations with the information given:
<em>"Two kg of tea and 3 kg of sugar cost rupees 39 in january 1997":
</em>
2 t + 3 s =39 (a)
Where:
- t= price of 1 kg of tea
- s = price of 1 kg of sugar
<em>"in march 1997 the price of the tea increased by 25% (1.25)and the price of the sugar increased by 20%(1.20) and the same quantity of tea and sugar cost rupees 48.30.
"</em>
2(t1.25)+3(s1.2) = 48.30 (b)
- <em>Solving for t in (b)
</em>
2t =39-3s
t = (39 -3s)/2
t = 19.5-1.5s
- <em>Replacing the value of t in (b)
</em>
2 x ((19.5-1.5s)1.25)+ 3 ( 1.2s) =48.30
2x ( 24.375 -1.875s) +3.6s =48.30
48.75 -3.75s+3.6s= 48.30
48.75-48.30 = 3.75s-3.6s
0.45= 0.15s
0.45/0.15 =s
3 =s
- <em>Replacing the value of s in (a)
</em>
2 t + 3 (3) =39
2 t + 9 =39
2 t =39 -9
2 t =30
t = 30/2
t= 15
Prices in january:
tea = 15 rupees per kg
sugar= 3 rupees per kg
Feel free to ask for more if needed or if you did not understand something.
Given,
y = -3x+1 (EQ1)
y = 2x-4 (EQ2)
Equate EQ1 and EQ2
EQ1 = EQ2
-3x+1 = 2x-4
-3x-2x = -4-1
x = 1
y = -3x+1
y = -3(1)+1
y = -3+1
y = -2
(1, -2)
~B
