Consider the following functions f (x)=3x+2 g(x)=x^2-5 h(x)=x^2+4x+17 t(x)=x-6
1 answer:
Answer:
As noted in the comments, we need to find out which of those functions return a value of 14 when x is equal to 3.
No one of these functions gives ups a value of 3, but if we use them in combination, we can say that f(g(3)) gives us an end value of 14.
It may be that other combinations will give you the same result, but that is the most obvious one.
Step-by-step explanation:
Let's test each one:
None of these give a return value of 14 when x equals 3. Perhaps though, we can combine them to get the desired result?
Let's try f(g(3)):
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Answer:
36
Step-by-step explanation:
Let's let n be any number.
If we multiply n by 2, we get 2n. Since anything multiplied by 2 is even, 2n <em>must</em> be even. Therefore, let 2n be our first number.
So, the consecutive even number will be (2n+2) followed by (2n+4).
We know that their sum must be 114. Therefore, we can write the following equation:
Solve for n. Combine like terms on the left:
Subtract 6 from both sides:
Finally, divide both sides by 6. Therefore, the value of n is:
Therefore, our first even number is 2n or 2(18) which equates to 36.
And the consecutive even numbers will be 38 and 40.
So, the smallest of them, the first term, is 36.