Question

Consider the following functions f (x)=3x+2 g(x)=x^2-5 h(x)=x^2+4x+17 t(x)=x-6​

Answer 1

Answer:

As noted in the comments, we need to find out which of those functions return a value of 14 when x is equal to 3.

No one of these functions gives ups a value of 3, but if we use them in combination, we can say that f(g(3)) gives us an end value of 14.

It may be that other combinations will give you the same result, but that is the most obvious one.

Step-by-step explanation:

Let's test each one:

$f(3) = 3*3 + 2\\= 9 + 2\\= 11$

$g(3) = (3)^2 - 5\\= 9 - 5\\= 4$

$h(3) = 3^2 + 4(3) + 17\\=9 + 12 + 17\\38$

$t(3) = 3 - 6\\= -3$

None of these give a return value of 14 when x equals 3.  Perhaps though, we can combine them to get the desired result?

Let's try f(g(3)):

$f(g(3))\\= f(4)\\= 4 * 3 + 2\\= 12 + 2\\= 14$