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schepotkina [342]
3 years ago
15

Seamstress Jane has purchased 50 yards of red fabric and 110 yards of gold fabric to make red and gold curtains. What is the lar

gest number of curtains she can make if she wants all the curtains to be exactly the same length, and to have no fabric left over? How many yards of each kind of fabric would be used for each curtain/?
Mathematics
1 answer:
Alisiya [41]3 years ago
4 0

Answer: There are 10 largest number of curtains she can make if she wants all the curtains to be exactly the same length.

There are 5 red fabrics and 11 gold fabrics that would be used for each curtain.

Step-by-step explanation:

Since we have given that

Number of yards of red fabric purchased by Jane = 50

Number of yards of gold fabric purchased by Jane = 110

We need to find the largest number of curtains she can make if she wants all the curtains to be exactly the same length.

For this we will find H.C.F. of 50 and 110.

Factors of 50 = 1, 2, 5, 10, 25, 50.

Factors of 110 = 1, 2, 5, 10, 11, 22, 55, 110.

So, Highest common factor of 50 and 110 is 10.

So, there are 10 largest number of curtains she can make if she wants all the curtains to be exactly the same length.

Number of yards of red fabric is given by

\frac{50}{10}=5

Number of yards of gold fabric is given by

\frac{110}{10}=11

Hence, there are 5 red fabrics and 11 gold fabrics that would be used for each curtain.

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First, find the difference between each number in the sequence.... 34 - 25 = 9. 25 - 16 = 9 and 16 - 7 = 9... So, there is a constant difference of 9 between each number of the sequence. To find the 30th term, you could expand the sequence out to 30 (which is a good way to check your answer, but tedious)... So, simply add the 1st value of the sequence to the difference and multiply by 30 to find your 30th value.... 7 + 9 x 30 = 16 x 30 = 480.

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Answer:

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Step-by-step explanation:

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The current coordinates are-

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