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schepotkina [342]
3 years ago
15

Seamstress Jane has purchased 50 yards of red fabric and 110 yards of gold fabric to make red and gold curtains. What is the lar

gest number of curtains she can make if she wants all the curtains to be exactly the same length, and to have no fabric left over? How many yards of each kind of fabric would be used for each curtain/?
Mathematics
1 answer:
Alisiya [41]3 years ago
4 0

Answer: There are 10 largest number of curtains she can make if she wants all the curtains to be exactly the same length.

There are 5 red fabrics and 11 gold fabrics that would be used for each curtain.

Step-by-step explanation:

Since we have given that

Number of yards of red fabric purchased by Jane = 50

Number of yards of gold fabric purchased by Jane = 110

We need to find the largest number of curtains she can make if she wants all the curtains to be exactly the same length.

For this we will find H.C.F. of 50 and 110.

Factors of 50 = 1, 2, 5, 10, 25, 50.

Factors of 110 = 1, 2, 5, 10, 11, 22, 55, 110.

So, Highest common factor of 50 and 110 is 10.

So, there are 10 largest number of curtains she can make if she wants all the curtains to be exactly the same length.

Number of yards of red fabric is given by

\frac{50}{10}=5

Number of yards of gold fabric is given by

\frac{110}{10}=11

Hence, there are 5 red fabrics and 11 gold fabrics that would be used for each curtain.

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A= [2, 3; 2, 1], B=[3; 5]. Find AB & BA if possible
oksano4ka [1.4K]

Answer:

The value of AB is \left[\begin{array}{ccc}21\\11\end{array}\right] and it's not possible to multiply BA.

Step-by-step explanation:

Consider the provided matrices.

A=\left[\begin{array}{ccc}2&3\\2&1\end{array}\right], B=\left[\begin{array}{ccc}3\\5\end{array}\right]

Two matrices can be multiplied if and only if first matrix has an order m × n and second matrix has an order n × v.

Multiply AB

Matrix A has order 2 × 2  and matrix B has order 2 × 1. So according to rule we can multiply both the matrix as shown:

AB=\left[\begin{array}{ccc}2&3\\2&1\end{array}\right] \left[\begin{array}{ccc}3\\5\end{array}\right]

AB=\left[\begin{array}{ccc}2\times 3+3\times 5\\2\times 3+1\times 5\end{array}\right]

AB=\left[\begin{array}{ccc}6+15\\6+5\end{array}\right]

AB=\left[\begin{array}{ccc}21\\11\end{array}\right]

Hence, the value of AB is \left[\begin{array}{ccc}21\\11\end{array}\right]

Now calculate the value of BA as shown:

Multiply BA

Matrix B has order 2 × 1  and matrix A has order 2 × 2. So according to rule we cannot multiply both the matrix.

We can multiply two matrix if first matrix has an order m × n and second matrix has an order n × v.

That means number of column of first matrix should be equal to the number of rows of second matrix.

Hence, it's not possible to multiply BA.

5 0
4 years ago
I need the answer to 23 divided by 12
Ugo [173]
The answer is about 1.9166
8 0
3 years ago
Helpppppp hurry and no links
Alexeev081 [22]

Step-by-step explanation:

6.3%

that is the correct answer

4 0
3 years ago
Read 2 more answers
18x^2+24x=0 Please solve by factoring.
Harman [31]

Answer:

6x ( 3x +4)

X =0 and x = 4/3 or x = 1 1/3

Step-by-step explanation:

Take the common factors out,

Here x is common to both equation and also 6 is common to both equation

So,

6x ( 3x + 4) = 0

So it can be solved by

X = 0 and x = 4/3

4 0
3 years ago
If r=20.5 and s=34.2 find S Round to the nearest tenth
astraxan [27]

Answer: option d

Step-by-step explanation:

Remember the identity:

tan\alpha=\frac{opposite}{adjacent}

The inverse of the tangent function is arctangent. You need to use this to calculate the angle "S":

 \alpha =arctan(\frac{opposite}{adjacent})

Knowing that: you need to find the measure of the angle "S" , r=20.5 (which is the adjacent side) and s=34.2 (which is the opposite side), you can sustitute values into \alpha =arctan(\frac{opposite}{adjacent})

Then, you get that the measure of "S" rounded to the nearest tenth is:

S=arctan(\frac{34.2}{20.5})\\\\S=59.1\°

7 0
4 years ago
Read 2 more answers
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