Answer:
B) -5, 5, -7, 7
Step-by-step explanation:
3x² - bx + 2
factor:
(3x - 2 )(x - 1) = 3x² - (5)x + 2 so 5 does work
(3x - 1 )(x - 2) = 3x² - (7)x + 2 so 7 does work
(3x + 2 )(x + 1) = 3x² + 5x +2 = 3x² - (-5)x + 2 so -5 does work
(3x + 1 )(x + 2) = 3x² + 7x + 2 = 3x² - (-7)x + 2 so -7 does work
Answer:
24
Step-by-step explanation:
The question is saying, how many three digit numbers can be made from the digits 3, 4, 6, and 7 but there can't be two of the same digit in them. For example 346 fits the requirements, but 776 doesn't, because it has two 7s.
Okay, on to the problem:
We can do one digit at a time.
First digit:
There are 4 digits that we can choose from. (3, 4, 6, and 7)
Second digit:
No matter which digit we chose for the first digit, there is only going to be 3 of them left, because we already chose one, and you can't repeat that same digit. So there are 3 options.
Third digit:
Using the same logic, there are only 2 options left.
We have 4 choices for the first digit, 3 choices for the second, and 2 for the third.
Hence, this is 4 * 3 * 2 = 24 three-digit numbers that can be made.
Answer all questions??
Step-by-step explanation:
b, c , a b,c,c,d
Answer:
Step-by-step explanation:
Check attachment for solution
Answer:the answer is A
Step-by-step explanation:
I know because i took the quiz and got it right
