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3 years ago

X² + 2x – 1 = 0 in English words.

Mathematics

2 answers:

Svet_ta [14]3 years ago

7 0

Answer:

x squared plus two times x minus one = zero.

Step-by-step explanation:

(This is a Quadratic equation in the variable x).

Doss [256]3 years ago

3 0

Answer:

One less than the sum of square of a number and twice the number is 0

Step-by-step explanation:

$x^2+ 2x - 1 = 0$

x represents any number. x^2 represents square of a number

2x represents twice the number

$x^2+2x$ can be written as sum of square of a number and twice the number

$x^2+2x-1$

One less than the sum of square of a number and twice the number

$x^2+2x-1=0$

One less than the sum of square of a number and twice the number is 0

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What is 2x-64<108 If you answer this I will give you a total of 23 points!

alexandr1967 [171]

Answer:

2x-64<108

One solution was found :

x < 86

Rearrange:

Rearrange the equation by subtracting what is to the right of the greater than sign from both sides of the inequality :

2*x-64-(108)<0

Step by step solution :

Step 1 :

Pulling out like terms :

1.1 Pull out like factors :

2x - 172 = 2 • (x - 86)

Equation at the end of step 1 :

Step 2 :

2.1 Divide both sides by 2

Solve Basic Inequality :

2.2 Add 86 to both sides

x < 86

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telo118 [61]

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One basketball weighs 20.2 ounces. The basketball team has a total of 15 basketballs. If each basketball weighs the same, about

S_A_V [24]

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3 years ago

Read 2 more answers

Geometry question on finding x.

Dmitrij [34]

Answer:

$x =63^o$

Step-by-step explanation:

Given :-

$\text{ $\overline{MN} $ and $\overline{ML}$ are tangents .}$

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According to question :-

$\implies x + 117^o + 90^o +90^o = 360^o \\\\\implies x + 297^o = 360^o \\\\\implies x = 360^o - 297^o \\\\\implies x = 63^o$

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3 years ago

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mr Goodwill [35]

Answer:

Step-by-step explanation:

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T(x) = 160-0.05x^2

a. [0, 10]

For x = 0

T(0) = 160 - 0.05 × 0^2

T(0) = 160

For x = 10

T(10) = 160 - 0.05 × 10^2

T(10) = 160 - 5 = 155

The average temperature

= (160 + 155)/2 = 157.5

b. [10, 40]

For x = 10

T(10) = 160 - 0.05 × 10^2

T(10) = 160 - 5 = 155

For x = 40

T(10) = 160 - 0.05 × 40^2

T(10) = 160 - 80 = 80

The average temperature

= (80 + 155)/2 = 117.5

c. [0, 40]

For x = 0

T(0) = 160 - 0.05 × 0^2

T(0) = 160

For x = 40

T(10) = 160 - 0.05 × 40^2

T(10) = 160 - 80 = 80

The average temperature

= (160 + 80)/2 = 120

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3 years ago