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Reil [10]
3 years ago
6

Plz answer this question step by step.

Mathematics
1 answer:
pychu [463]3 years ago
8 0

I cant see the picture it is blurry


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FP!!!!!!!!!!!!!!!!!!! if ur up<br><br> ( 10 x 8 ) + 150
taurus [48]

Answer:

220

Step-by-step explanation:

<u>first we have by Bracket of BODMAS rule then we have to multiply 10 *8 = 80</u>

<u>first we have by Bracket of BODMAS rule then we have to multiply 10 *8 = 80then we have to open bracket 80 +150</u>

<u>first we have by Bracket of BODMAS rule then we have to multiply 10 *8 = 80then we have to open bracket 80 +150 = 220</u>

<u> (10*8) +15</u>

<u>Solution</u>

<u>Solution= (80) +150</u>

<u>Solution= (80) +150= 80+150</u>

<u>Solution= (80) +150= 80+150=. 220</u>

<u>Solution= (80) +150= 80+150=. 220 </u>

8 0
2 years ago
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Jill and Marcy go to an ice cream store where they have the option of getting a smoothie in either a cylindrical or rectangular
k0ka [10]

Answer: Jill got the larger smoothie and its volume is 1609.14 cubic cm.

Step-by-step explanation:

Since we have given that

Jill purchased the cylindrical container.

Height of container = 8 cm

Radius = 8 cm

So, volume of cylindrical container would be

\pi r^2h\\\\=\dfrac{22}{7}\times 8\times 8\times 8\\\\=1609.14\ cm^3

Marcy purchased the rectangular container.

Height of container = 8 cm

Width = 8 cm

Length = 8 cm

so, volume of rectangular container would be

l\times b\times h\\\\=8\times 8\times 8\\\\=512\ cm^3

Hence, Jill got the larger smoothie and its volume is 1609.14 cubic cm.

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What SPC tool best indicates the shape of the data population and indicates if there are any gaps in the data
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The gaps in the area needs to be closed so the data you use is lenient
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2 years ago
If (-3) exponent -5 = 1/x, what is the value of x? <br> -243<br> - 1/243<br> 1/243<br> 243
trapecia [35]

Answer:

\boxed {-243}\\

Step-by-step explanation:

\begin{array}{rclr}(-3)^{-5} & = & \dfrac{1}{x}& &\\(-3)^{5} & = & x &\text{Inverted each side of the equation}\\x & = & \boxed {\textbf{{-243}}}\\\end{array}

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Practice Solving Distance Problems
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