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kirill115 [55]
2 years ago
7

New York City is approximately 4.68×10²square miles. Los Angeles is 503 square miles.How many times larger is Los Angeles in New

York right answer in a scientific notation
Mathematics
1 answer:
eduard2 years ago
8 0
7.48×10⁻² the process is shown in the following picture

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Elimination method. -2y = 0.5 - 2x<br> 6х + Зу = 6
AysviL [449]

Answer:

y=-1.5

X=1.75

Step-by-step explanation:

Yuh arrange the equations in order for easy subtracting of the equations.

-2y=0.5-2x. divide both sides by 2 to get y=-x-0.25.

6x+3y=6

3y=-6x+6 then divide both sides by three to get y

y=-2x+2

now arrange

y=-2x+2

y=-x-0.25 then multiple both equations by the cordinates of X value to eliminate x

8 0
3 years ago
What is the domain of this table​
Crank

Answer:

the answer is b

8 0
3 years ago
Read 2 more answers
How to find the slope of a line that is parallel to y equals 2x - 3 and runs through the point(-2,0)
Ganezh [65]
Recognize that parallel lines have the same slope.  Then:

Method 1:  write y = 2x + c and find c from the given information:

y = 2x + c becomes 0 = 2(-2) + c, so that c = 4.  Then y = 2x + 4 (answer)


Method 2:     Slope is 2 and a point on the line is (-2,0):

Use the point-slope formula:  y - 0 = 2(x+2), or y = 2(x+2), or y=2x+4 (ans)
4 0
4 years ago
What is the correct answer
kompoz [17]
-2 + 2.5= 0.5 and -7 + (-1.5) = -8.5

so B is at (0.5, -8.5)
8 0
3 years ago
Given 1+cosx\sinx+sinx\1+cosx=4, find a numerical value of one trigonometric function of x.
Len [333]

Answer:

Option d. sin(x)=\frac{1}{2}

Step-by-step explanation:

<u><em>The complete question is</em></u>

Given (1+cosx)/(sinx) + (sinx)/(1+cosx) =4, find a numerical value of one trigonometric function of x.

a. tanx=2

b. sinx=2

c. tanx=1/2

d. sinx=1/2

we have

\frac{1+cos(x)}{sin(x)}+\frac{sin(x)}{1+cos(x)}=4

Find the common denominator and adds the fractions

\frac{(1+cos(x))^2+sin^2(x)}{(1+cos(x))sin(x)}=4

Expanded the numerator

\frac{(1+2cos(x)+cos^2(x)+sin^2(x)}{(1+cos(x))sin(x)}=4

Remember that

sin^2(x)+cos^2(x)=1 ----> trigonometric identity

substitute

\frac{1+2cos(x)+1}{(1+cos(x))sin(x)}=4

\frac{2+2cos(x)}{(1+cos(x))sin(x)}=4

Factor 2 in the numerator

\frac{2(1+cos(x))}{(1+cos(x))sin(x)}=4

Simplify

\frac{2}{sin(x)}=4

sin(x)=\frac{1}{2}

7 0
3 years ago
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